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Remember the rule:

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If $y = ax^n$ then $\\frac{dy}{dx} = anx^{n-1}$

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Differentiate each of the following:

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i) 

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$y = x^{\\frac{1}{\\var{p1}}}$

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$\\frac{dy}{dx} = \\var{ans11}x^{(\\frac{1}{\\var{p1}}-1)} = \\var{ans11}x^{\\var{ans12}}$

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ii) 

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$y = x^{\\frac{\\var{p2[0]}}{\\var{p2[1]}}}$

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$\\frac{dy}{dx} = \\frac{\\var{p2[0]}}{\\var{p2[1]}}x^{(\\frac{\\var{p2[0]}}{\\var{p2[1]}}-1)} = \\var{ans21}x^{\\var{ans22}}$

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iii) 

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$y = \\var{num[0]}x^{\\var{p3}}$

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$\\frac{dy}{dx} = \\var{ans31}x^{(\\var{p3}-1)} = \\var{ans31}x^{\\var{ans32}}$

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iv) 

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$y = \\var{num[1]}\\sqrt(x) = \\var{num[1]}x^{\\frac{1}{2}}$

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$\\frac{dy}{dx} = \\frac{\\var{num[1]}}{2}x^{(\\frac{1}{2}-1)} = \\var{ans41}x^{\\var{ans42}}$

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v) 

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$y = \\frac{\\var{n51}}{x^{\\var{n52}}} = \\var{n51}x^{-\\var{n52}}$

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$\\frac{dy}{dx} = \\var{ans51}x^{(-\\var{n52}-1)} = \\var{ans51}x^{\\var{ans52}}$

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vi) 

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$y = \\sqrt(x^\\var{n6}) = x^{\\frac{\\var{n6}}{2}}$

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$\\frac{dy}{dx} = \\frac{\\var{n6}}{2}x^{(\\frac{\\var{n6}}{2}-1)} = \\var{ans61}x^{\\var{ans62}}$

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$y = \\var{num[0]}x^{\\var{p3}}$

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$\\frac{dy}{dx} =$ [[0]] 

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$y = \\var{num[1]}\\sqrt x$

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$\\frac{dy}{dx} =$ [[0]] 

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Hint: What is $\\sqrt x$ as a power of $x$

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$y = \\frac{\\var{n51}}{x^{\\var{n52}}}$

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$\\frac{dy}{dx} =$ [[0]] 

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Hint: What is $\\frac{1}{x^2}$ as a power of $x$

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