// Numbas version: exam_results_page_options {"name": "The Factor Theorem", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"tags": ["Factors", "factors", "polynomial long division", "polynomials", "remainders", "roots"], "metadata": {"licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International", "description": ""}, "statement": "", "parts": [{"scripts": {}, "variableReplacementStrategy": "originalfirst", "distractors": ["", "", "", ""], "maxMarks": 0, "stepsPenalty": 0, "showCorrectAnswer": true, "variableReplacements": [], "shuffleChoices": false, "matrix": ["1", 0, 0, 0], "showFeedbackIcon": true, "type": "1_n_2", "prompt": "

Suppose a polynomial $f(x)$ evaluated at $\\var{c}$ is $0$, that is, $f(\\var{c})=0$. 

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Which of the following is guaranteed? 

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The Factor Theorem says that $x-a$ is a factor of a polynomial $f(x)$ if and only if $f(a)=0$. 

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Since we are told that $f(\\var{c})=0$ then we know $\\simplify{x-{c}}$ is a factor of $f(x)$.

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$\\simplify{x-{c}}$ is a factor of $f(x)$

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$\\simplify{x+{c}}$ is a factor of $f(x)$

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$x$ is a factor of $f(x)$

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$\\var{c}$ is a factor of $f(x)$

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Suppose $\\simplify{x-{d}}$ is a factor of a polynomial $g(x)$. That is, if we divided $g(x)$ by $\\simplify{x-{d}}$ the remainder would be $0$.

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This guarantees us that $g\\large($ [[0]] $\\large)=$ [[1]].

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The Factor Theorem says that $x-a$ is a factor of a polynomial $f(x)$ if and only if $f(a)=0$.  

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Since we are told $\\simplify{x-{d}}$ is a factor of $g(x)$, we know that $g(\\var{d})=0$.

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