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You start by writing down the values you know and the values you need to find.

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$a =$ $?$, $u=\\var{u},$ $t=\\var{t},$ $v=\\var{v},$ $s=$ $?$

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a) You need the distance $s \\mathrm{m}$ and you know $u, v$ and $t$ so you can use the equation $s= \\left(\\frac{u+v}{2}\\right)t$. \\begin{align} s &= \\left(\\frac{u+v}{2}\\right)t, \\\\
                         &= \\left(\\frac{\\var{u}+\\var{v}}{2}\\right) \\times \\var{t}, \\\\
                         &= \\var{(u+v)*0.5*t} \\mathrm{m}.\\end{align}

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The distance the truck travels is $\\var{(u+v)*0.5*t}$ metres.

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b) You need the acceleration, $a \\mathrm{ms^{-2}}$, and you know $u$,$v$ and $t$ so you can use the equation $v=u + at$ rearranged for $a$.

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\\begin{align} a &= \\left(\\frac{v-u}{t}\\right),  \\\\
                       &= \\left(\\frac{\\var{v}-\\var{u}}{\\var{t}}\\right), \\\\
                       &= \\frac{\\var{(v-u)}}{\\var{t}} \\mathrm{ms^{-2}}. \\end{align}
The acceleration of the truck is $\\frac{\\var{(v-u)}}{\\var{t}} \\mathrm{ms^{-2}}$.

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Find the distance in $\\mathrm{m}$ that the truck travels in these $\\var{t}$ seconds.

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Find the acceleration in $\\mathrm{ms^{-2}}$ of the truck in these $\\var{t}$ seconds.

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A truck accelerates along a straight road at a constant rate from a speed of $\\var{u} \\mathrm{ms^{-1}}$ to $\\var{v} \\mathrm{ms^{-1}}$ in $\\var{t}$ seconds.

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initial velocity

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time

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final velocity

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