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a) We have that $t=\\var{t}, s=\\var{s}$ and $v=\\var{v}$. We are asked to find the acceleration of the car, $a$, therefore we can use the formula $s=vt-\\frac{1}{2}at^2$, rearranged for $a$.
\nThis gives \\begin{align} s &= vt - \\frac{1}{2}at^2, \\\\
\\frac{1}{2}at^2 &= vt - s ,\\\\
a & = \\frac{2(vt-s)}{t^2}, \\\\
& = \\frac{2(\\var{v} \\times \\var{t} - \\var{s})}{\\var{t}^2}, \\\\
& = \\var{precround((2(v*t-s))/(t^2),3)}\\mathrm{m^{-2}}. \\end{align}
So the acceleration of the car is $\\var{precround((2(v*t-s))/(t^2),3)} \\mathrm{ms^{-2}}$.
\nb) We are asked to find the initial velocity, $u$. We could use the formula $v=u+at$, however it is best to work with the data given in the question in case our answer to part a) is incorrect. Therefore we will use $s=\\left(\\frac{u+v}{2}\\right)t$ rearranged for $u$.
\nThis gives \\begin{align} s & = \\left(\\frac{u+v}{2}\\right)t, \\\\
u & = \\frac{2s}{t} - v, \\\\
& = \\frac{2 \\times \\var{s}}{\\var{t}} - \\var{v}, \\\\
& = \\var{precround((2*s)/t-v,3)} \\mathrm{ms^{-1}}. \\end{align}
The car was travelling at $\\var{precround((2*s)/t-v,3)} \\mathrm{ms^{-1}}$ when it passed the traffic lights.
Find the acceleration in $\\mathrm{ms^{-2}}$ (to 3d.p.) of the car.
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