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Simultaneous equation problem as circuit analysis to find unknown currents. Students need to solve the equations and type in the solutions for each variable. Advice is given in terms of solution by elimination.
", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "", "advice": "We need to solve \\begin{align} \\simplify[unitFactor]{-{a}I_2 + {b}I_1} &= 0\\\\ \\simplify[unitFactor]{{c}I_1 - {d}I_2 + {f}} &=0\\end{align} which can be written as \\begin{align} \\simplify[unitFactor]{{b}I_1-{a}I_2} &= 0\\quad (1)\\\\ \\simplify[unitFactor]{{c}I_1 - {d}I_2} &=\\simplify{-{f}}\\quad (2)\\end{align}
\nUsing the method of elimination to eliminate \\(I_2\\) we multiply equation \\((1)\\) by \\(\\var{factor2}\\) and equation \\((2)\\) by \\(\\var{factor1}\\) to get \\begin{align}\\simplify[unitFactor]{{b*factor2}I_1-{a*factor2}I_2} &= 0\\quad (3)\\\\ \\simplify[unitFactor]{{c*factor1}I_1 - {d*factor1}I_2} &=\\simplify{-{f*factor1}}\\quad (4)\\end{align}
\nTaking \\((3)-(4)\\) we obtain \\[\\simplify{({b*factor2}-{c*factor1})I_1={f*factor1}}\\]
\nand hence \\[I_1=\\var{rational(a*f/(b*d-a*c))}\\]
\nSubstituting this into \\((1)\\) gives us \\[\\simplify[unitFactor]{-{a}I_2 + {b*a*f/(b*d-a*c)}} = 0\\] and hence \\[I_2=\\simplify{{b*f/(b*d-a*c)}}\\]
\nThus the currents are \\(I_1=\\simplify{{a*f/(b*d-a*c)}}\\) amps and \\(I_2=\\simplify{{b*f/(b*d-a*c)}}\\) amps.
\n(Note that this problem could also be solved by eliminating \\(I_1\\) instead of \\(I_2\\) or by the method of substitution, however the final answers will be the same.)
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", "templateType": "anything", "can_override": false}}, "variablesTest": {"condition": "b*d-a*c<>0", "maxRuns": 100}, "ungrouped_variables": ["c", "a", "b", "d", "f", "factor1", "factor2"], "variable_groups": [], "functions": {}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "Analysis of a particular electronic circuit shows that the currents across two sections of the circuit must satisfy the equations \\begin{align} \\simplify[unitFactor]{-{a}I_2 + {b}I_1} &= 0\\\\ \\simplify[unitFactor]{{c}I_1 - {d}I_2 + {f}} &=0 \\end{align} Find the values of \\(I_1\\) and \\(I_2\\). Write your final answer in the box below and show full working on your handwritten notes. (Note: Leave answers in fraction form. For example to enter the fraction \\(\\frac32\\) type 3/2
.)
\\(I_1=\\)[[0]] amps
\n\\(I_2=\\)[[1]] amps
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