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Direct Factorisation.

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Factorise the quadratic expression : $\\simplify{{a*b} * x ^ 2 + ( {-b*c-a * d}) * x + {c * d}}$ by trial and error.....

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We get: $\\simplify{{a*b} * x ^ 2 + ( {-b*c-a * d}) * x + {c * d} = ({a} * x + { -c}) * ({b} * x + { -d})}$

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Now we solve the quadratic equation: $\\simplify{({a} * x + { -c}) * ({b} * x + { -d})}=0 $   as follows:

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We conclude from the previous equation that: 

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$\\simplify{({a} * x + { -c})} =0$      or   $\\simplify{({b} * x + { -d})}=0$   giving 

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$\\simplify{{a} * x = {c}}$           or   $\\simplify{{b} * x = {d}}$    so

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$\\simplify{x ={c}/{a}} $             or    $\\simplify{ x ={d}/{b}} $  

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The roots are, in ascending order,  $ x = \\simplify[fractionNumbers]{{min({c}/{a},{d}/{b})}}$  and  $ x = \\simplify[fractionNumbers]{{max({c}/{a},{d}/{b})}}$ 

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\\[\\simplify{{a*b} * x ^ 2 + ( {-b*c-a * d}) * x + {c * d}}=0\\]

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The factors are:  [[0]]

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The roots are:   Smallest Root:  [[1]]    Largest Root:   [[2]] 

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Factorise the expression into two factors.

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factorise the expression into two factors

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Solve the following quadratic equation by factorisation.

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Solve $\\displaystyle{ax ^ 2 + bx + c=0}$ by factorisation. 

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