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$\\var{num1p[0]}(\\var{num1p[1]}x + \\var{num1p[2]}) \\var{num1n[0]}(\\var{num1p[3]} \\var{num1n[1]}x) + \\var{num1p[4]}$

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$(\\var{p4[0]}x \\var{n4[0]})(\\var{p4[1]}x +\\var{p4[2]})$

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Don't forget to fully square out the bracket. $(ax + b)^2 = (ax + b)(ax + b)$

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$(\\var{n5[0]}x + \\var{p5[0]})^2$

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First you need to find a common denominator. To do this you need to find the lowest common multiple of the three denominator.

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Watch video for help

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Video

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Express $\\frac{\\var{nm[0]}x}{\\var{dm[0]}} + \\frac{\\var{nm[1]}x}{\\var{dm[1]}}$ as a single fraction.

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$\\frac{\\var{p2[0]}x+ \\var{p2[1]}}{\\var{div[0]}}+\\frac{\\var{p2[2]} \\var{n2[0]}x}{\\var{div[1]}}-\\frac{\\var{p2[3]}x+ \\var{p2[4]}}{\\var{div[2]}}$

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$\\frac{\\var{t3[0]}}{\\var{d3[0]}}(\\var{p3[0]}x \\var{n3[0]})-\\frac{\\var{t3[1]}}{\\var{d3[1]}}(\\var{p3[1]} \\var{n3[1]}x)-\\frac{\\var{t3[2]}}{\\var{d3[2]}}(\\var{p3[2]}x + \\var{p3[3]})$ 

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Simplifying algebraic expressions

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For the following, leave the numbers as is, do not put into lowest form as these are algebra expressions:

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For example:

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When you simplify the equation and the answer is $3x -6$, leave it as that, do not answer $x - 2$.

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Remove the brackets and gather the x terms together and also the number terms together.

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When in fraction form, get the lowest common multiple (LCM), and multiply the top line by how many times the divisor goes into the LCM.

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Rule for multiping out brackets:

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(a$x$ - b)(c$x$ + d) = (a * c)$x^2$ + ((a * d) + ((-b) *c)))$x$ + ((-b) * d)

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Rule for squaring brackets:

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(-a$x$ + b)$^2$ = (-a * -a)$x^2$ + (2 * (-a) *b)$x$ + (b * b)

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