// Numbas version: exam_results_page_options {"name": "Pushing a box up an inclined plane", "extensions": [], "custom_part_types": [], "resources": [["question-resources/force_acting_on_incline.png", "/srv/numbas/media/question-resources/force_acting_on_incline.png"], ["question-resources/force_acting_on_an_incline_solution.png", "/srv/numbas/media/question-resources/force_acting_on_an_incline_solution.png"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"functions": {}, "ungrouped_variables": ["mass", "P", "theta", "R"], "name": "Pushing a box up an inclined plane", "tags": [], "advice": "

a)

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We can draw a diagram to show the forces acting on the box. The plane is smooth so there is no friction. 

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To find the normal reaction between the box and the plane we solve $F=ma$ perpendicular to the plane.

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\\begin{align}
F &  = ma, \\\\
R - mg \\cos \\theta - P \\cos(90^{\\circ} - \\theta) & = m \\times 0, \\\\
R & = mg \\cos \\theta - P \\cos(90^{\\circ} - \\theta), \\\\
& = (\\var{mass} \\times 9.8 \\cos(\\var{theta}^{\\circ})) - (\\var{P} \\cos(\\var{90-theta}^{\\circ})), \\\\
& = \\var{R}\\mathrm{N}.
\\end{align}

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The normal reaction, $R$, is $\\var{R}\\mathrm{N}$ to 3d.p.

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b)

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To find the acceleration of the box up the plane we resolve parallel to the plane. The plane is smooth so there is no friction. 

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\\begin{align}
F& = ma,\\\\
P \\cos \\theta - mg \\cos (90^{\\circ} - \\theta) & = ma, \\\\
a & = \\frac{ P \\cos \\theta - mg \\cos (90^{\\circ} - \\theta)}{m}, \\\\
&= \\frac{ \\var{P} \\cos(\\var{theta}^{\\circ}) - (\\var{mass} \\times 9.8 \\cos(\\var{90-theta}^{\\circ}))}{\\var{mass}}, \\\\
&= \\var{precround((P*cos(radians(theta))-mass*9.8*cos(radians(90-theta)))/mass,3)}\\mathrm{ms^{-2}}.
\\end{align}

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The acceleration of the box up the plane is $\\var{precround((P*cos(radians(theta))-mass*9.8*cos(radians(90-theta)))/mass,3)}\\mathrm{ms^{-2}}.$

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Find the normal reaction between the box and the plane, in $\\mathrm{N}$ to 3 decimal places.

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Assuming the plane is smooth, find the acceleration of the box up the plane, in $\\mathrm{ms^{-2}}$ to 3 decimal places.

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A box of mass $\\var{mass}\\mathrm{kg}$ is being pushed up an inclined plane by a horizontal force $P = \\var{P}\\mathrm{N}$. The plane is inclined at an angle of $\\theta=\\var{theta}^{\\circ}$. above the horizontal. 

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In the following the acceleration due to gravity is taken as $g=9.8\\mathrm{ms^{-2}}$.

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A box is being pushed up a slope by a horizontal force. Calculate the normal reaction force, and the acceleration of the box up the slope.

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