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Hoogte, valtijd en gemiddelde snelheid berekenen.

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Je laat een bal van een toren vallen. De hoogte $h$ van de bal ten opzichte van de grond (in meter) na $t$ seconden wordt beschreven door de functie met voorschrift $h(t)=-4,9t²+\\var{hoogte}$.

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De hoogte is de constante term uit de vergelijking (op $t=0$ bevindt de bal zich bovenaan de toren), dus {hoogte} m.

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De valtijd bedraagt $h = 0 <=> 0 = -4,9t² + \\var{hoogte} <=> t² = \\frac{\\var{hoogte}}{4,9} <=> t = \\sqrt{\\frac{\\var{hoogte}}{4,9}}=\\var{formatnumber(precround(grond,1),\"plain-eu\")}$ s.

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De gemiddelde snelheid is het differentiequotiënt over het interval $[0; \\var{tijd}]$.

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$\\frac{f(\\var{tijd})-f(0)}{\\var{tijd}-0}=\\frac{-4,9 \\cdot \\var{tijd}²+\\var{hoogte}-\\var{hoogte}}{\\var{tijd}}=-4,9 \\cdot \\var{tijd} = \\var{formatnumber(precround(snelheid,2),\"plain-eu\")}$$\\frac{m}{s}$

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Hoe hoog is de toren?

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[[0]] m

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Na hoeveel seconden raakt de steen de grond?

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[[0]] s

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Geef je antwoord op 1 decimaal nauwkeurig.

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Wat is de gemiddelde snelheid van de bal in de eerste {formatnumber(tijd,\"plain-eu\")} seconden van de val?

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Geef je antwoord op twee decimalen nauwkeurig.

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De gemiddelde snelheid van de bal in de eerste {formatnumber(tijd,\"plain-eu\")} seconden van de val bedraagt [[0]] $\\frac{m}{s}$.

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