// Numbas version: finer_feedback_settings {"name": "GB1 Trigonometry - missing side", "extensions": ["eukleides"], "custom_part_types": [], "resources": [["question-resources/Picture1_caMIdF1.png", "/srv/numbas/media/question-resources/Picture1_caMIdF1.png"], ["question-resources/Picture2_6KE4ZpW.png", "/srv/numbas/media/question-resources/Picture2_6KE4ZpW.png"]], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "GB1 Trigonometry - missing side", "tags": [], "metadata": {"description": "
Draws a triangle based on 3 side lengths. Randomises asking angle or side.
", "licence": "Creative Commons Attribution 4.0 International"}, "statement": "{max_height(25,diagram)}
", "advice": "Avoid using rounded values in calculations and just round for the final answer.
{advice}
In this situation $x$ is an angle. We label the known sides of the triangle \\'opposite\\', \\'adjacent\\' and \\'hypotenuse\\' in relation to the angle we are interested in:
\\n$\\\\text{Opposite} = \\\\var{bc}$
$\\\\text{Hypotenuse} = \\\\var{ab}$
We have \\'O\\' and \\'H\\' in SOHCAHTOA, so we know we need to use the $\\\\sin$ formula:
\\\\[ \\\\sin(\\\\text{Angle}) = \\\\frac{\\\\text{Opposite}}{\\\\text{Hypotenuse}}\\\\]
\\nNow we subsitute the values we have in this particular question
\\n\\\\[ \\\\sin(x) = \\\\frac{\\\\var{bc}}{\\\\var{ab}}\\\\]
We need to use the \\'inverse $\\\\sin$\\' button on the calculator (also called $\\\\arcsin$ or notated $\\\\sin^{-1}$) in order to isolate $x$:
Make sure your calculator is set to \\'degree\\' mode, if you get an odd answer you are likely in the wrong mode!
\\\\[ x = \\\\sin^{-1}(\\\\var{bc}/\\\\var{ab})\\\\]
\\n\\\\[ x = \\\\var{precround(180*(arcsin(bc/(ab)))/pi,4)}\\\\]
\\nRound as required:
\\n\\\\[x = \\\\var{precround(180*(arcsin(bc/(ab)))/pi,2)}\\\\]
\"", "description": "", "templateType": "long string", "can_override": false}, "cos_a": {"name": "cos_a", "group": "advice", "definition": "\"In this situation $x$ is an angle. We label the known sides of the triangle \\'opposite\\', \\'adjacent\\' and \\'hypotenuse\\' in relation to the angle we are interested in:
\\n$\\\\text{Adjacent} = \\\\var{ac}$
$\\\\text{Hypotenuse} = \\\\var{ab}$
We have \\'A\\' and \\'H\\' in SOHCAHTOA, so we know we need to use the $\\\\cos$ formula:
\\\\[ \\\\cos(\\\\text{Angle}) = \\\\frac{\\\\text{Adjacent}}{\\\\text{Hypotenuse}}\\\\]
\\nNow we subsitute the values we have in this particular question
\\n\\\\[ \\\\cos(x) = \\\\frac{\\\\var{ac}}{\\\\var{ab}}\\\\]
We need to use the \\'inverse $\\\\cos$\\' button on the calculator (also called $\\\\arccos$ or notated $\\\\cos^{-1}$) in order to isolate $x$:
Make sure your calculator is set to \\'degree\\' mode, if you get an odd answer you are likely in the wrong mode!
\\\\[ x = \\\\cos^{-1}(\\\\var{ac}/\\\\var{ab})\\\\]
\\n\\\\[ x = \\\\var{precround(180*(arccos(ac/(ab)))/pi,4)}\\\\]
\\nRound as required:
\\n\\\\[x = \\\\var{precround(180*(arccos(ac/(ab)))/pi,2)}\\\\]
\"", "description": "", "templateType": "long string", "can_override": false}, "tan_a": {"name": "tan_a", "group": "advice", "definition": "\"In this situation $x$ is an angle. We label the known sides of the triangle \\'opposite\\', \\'adjacent\\' and \\'hypotenuse\\' in relation to the angle we are interested in:
\\n$\\\\text{Opposite} = \\\\var{bc}$
$\\\\text{Adjacent} = \\\\var{ac}$
We have \\'O\\' and \\'A\\' in SOHCAHTOA, so we know we need to use the $\\\\tan$ formula:
\\\\[ \\\\tan(\\\\text{Angle}) = \\\\frac{\\\\text{Opposite}}{\\\\text{Adjacent}}\\\\]
\\nNow we subsitute the values we have in this particular question
\\n\\\\[ \\\\tan(x) = \\\\frac{\\\\var{bc}}{\\\\var{ac}}\\\\]
We need to use the \\'inverse $\\\\tan$\\' button on the calculator (also called $\\\\arctan$ or notated $\\\\tan^{-1}$) in order to isolate $x$:
Make sure your calculator is set to \\'degree\\' mode, if you get an odd answer you are likely in the wrong mode!
\\\\[ x = \\\\tan^{-1}(\\\\var{bc}/\\\\var{ac})\\\\]
\\n\\\\[ x = \\\\var{precround(180*(arctan(bc/(ac)))/pi,4)}\\\\]
\\nRound as required:
\\n\\\\[x = \\\\var{precround(180*(arctan(bc/(ac)))/pi,2)}\\\\]
\"", "description": "", "templateType": "long string", "can_override": false}, "sin_bc": {"name": "sin_bc", "group": "advice", "definition": "\"In this situation $x$ is a side. We label the relevant sides of the triangle \\'opposite\\', \\'adjacent\\' and \\'hypotenuse\\' in relation to the angle we know:
\\n$\\\\text{Opposite} = x$
$\\\\text{Hypotenuse} = \\\\var{ab}$
We have \\'O\\' and \\'H\\' in SOHCAHTOA, so we know we need to use the $\\\\sin$ formula:
\\\\[ \\\\sin(\\\\text{Angle}) = \\\\frac{\\\\text{Opposite}}{\\\\text{Hypotenuse}}\\\\]
\\nNow we subsitute the values we have in this particular question
\\n\\\\[ \\\\sin(\\\\var{angle}) = \\\\frac{x}{\\\\var{ab}}\\\\]
and rearrange to give:
\\\\[ x = \\\\var{ab} \\\\times \\\\sin(\\\\var{angle}) \\\\]
Make sure your calculator is set to \\'degree\\' mode, if you get an odd answer you are likely in the wrong mode!
\\\\[ x = \\\\var{precround(ab*sin(pi*angle/180),4)}\\\\]
\\nRound as required:
\\n\\\\[ x = \\\\var{precround(ab*sin(pi*angle/180),2)}\\\\]
\"", "description": "", "templateType": "long string", "can_override": false}, "cos_ac": {"name": "cos_ac", "group": "advice", "definition": "\"In this situation $x$ is a side. We label the relevant sides of the triangle \\'opposite\\', \\'adjacent\\' and \\'hypotenuse\\' in relation to the angle we know:
\\n$\\\\text{Hypotenuse} = \\\\var{ab}$
$\\\\text{Adjacent} = x$
We have \\'A\\' and \\'H\\' in SOHCAHTOA, so we know we need to use the $\\\\cos$ formula:
\\\\[ \\\\cos(\\\\text{Angle}) = \\\\frac{\\\\text{Adjacent}}{\\\\text{Hypotenuse}}\\\\]
\\nNow we subsitute the values we have in this particular question
\\n\\\\[ \\\\cos(\\\\var{angle}) = \\\\frac{x}{\\\\var{ab}}\\\\]
and rearrange to give:
\\\\[ x = \\\\var{ab} \\\\times \\\\cos(\\\\var{angle}) \\\\]
Make sure your calculator is set to \\'degree\\' mode, if you get an odd answer you are likely in the wrong mode!
\\\\[ x = \\\\var{precround(ab*cos(pi*angle/180),4)}\\\\]
\\nRound as required:
\\n\\\\[ x = \\\\var{precround(ab*cos(pi*angle/180),2)}\\\\]
\"", "description": "", "templateType": "long string", "can_override": false}, "tan_ac": {"name": "tan_ac", "group": "advice", "definition": "\"In this situation $x$ is a side. We label the relevant sides of the triangle \\'opposite\\', \\'adjacent\\' and \\'hypotenuse\\' in relation to the angle we know:
\\n$\\\\text{Opposite} = \\\\var{bc}$
$\\\\text{Adjacent} = x$
We have \\'O\\' and \\'A\\' in SOHCAHTOA, so we know we need to use the $\\\\tan$ formula:
\\\\[ \\\\tan(\\\\text{Angle}) = \\\\frac{\\\\text{Opposite}}{\\\\text{Adjacent}}\\\\]
\\nNow we subsitute the values we have in this particular question
\\n\\\\[ \\\\tan(\\\\var{angle}) = \\\\frac{\\\\var{bc}}{x}\\\\]
and rearrange to give:
\\\\[ x = \\\\frac{\\\\var{bc}}{\\\\tan(\\\\var{angle})} \\\\]
Make sure your calculator is set to \\'degree\\' mode, if you get an odd answer you are likely in the wrong mode!
\\\\[ x = \\\\var{precround(bc/tan(pi*angle/180),4)}\\\\]
\\nRound as required:
\\n\\\\[ x = \\\\var{precround(bc/tan(pi*angle/180),2)}\\\\]
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\nAngles are given in degrees (make sure you calculator is in the right mode)
Give your answer correct to 2 decimal place.