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Calculating the derivative of a function of the form $a \\ln(bx)$ using a table of derivatives.

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Calculate the derivative of $y=\\simplify[unitFactor]{{a}*ln({a_1}*x^2+{a_2}*x+{a_3})}.$

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From the Table of Derivatives and the chain rule we see that a function of the form \\[ f(x)=a \\ln(g(x)) \\] has a derivative \\[\\frac{df}{dx}=\\frac{g'(x)}{g(x)}.\\]

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In this case $g(x)=\\var{a_1}x^2+\\var{a_2}x+\\var{a_3}$ so

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\\[g'(x)=\\var{2*a_1}x+\\var{a_2}\\]

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Therefore, the function \\[ \\simplify[unitFactor]{y={a}ln({a_1}*x^2+{a_2}*x+{a_3})}\\] has a derivative \\[(\\var{a*a_1*2}x+\\var{a*a_2})/(\\var{a_1}x^2+\\var{a_2}x+\\var{a_3})\\]

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Use this link to find some resources which will help you revise this topic.

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$\\frac{dy}{dx}=$[[0]]

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