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convert large numbers to scientific notation

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Write the following numbers in scientific notation.

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$\\var{q1} =$ [[0]]$\\times 10$ [[1]]

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A number is in scientific notation if it is written as a decimal multiplied by some power of 10, where the decimal has exactly one digit in front of the decimal place. For example:

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\\[1.234\\times 10^6, \\quad \\text{and} \\quad 3.01\\times 10^{-3}\\] 

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are both in scientific notation.

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Suppose we have the number $\\var{q1}$. In scientific notation, this number would start with $\\var{dec1}$ since we only want one digit in front of the decimal point. The decimal point is currently to the right of the last digit in $\\var{q1}$ and needs to move to between the first and second digits, that is $\\var{dec1}$. Count the places that the decimal point must jump and you get $\\var{pow1}$ places. That is,

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\\[\\var{q1}=\\var{dec1}\\times 10^{\\var{pow1}}\\]

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We have a positive $\\var{pow1}$ as the power because we need to make the number $\\var{dec1}$ bigger to get to $\\var{q1}$.

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$\\var{q2} =$ [[0]]$\\times 10$ [[1]] 

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A number is in scientific notation if it is written as a decimal multiplied by some power of 10, where the decimal has exactly one digit in front of the decimal place. For example:

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\\[1.234\\times 10^6, \\quad \\text{and} \\quad 3.01\\times 10^{-3}\\] 

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are both in scientific notation.

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\n
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Suppose we have the number $\\var{q2}$. In scientific notation, this number would start with $\\var{dec2}$ since we only want one digit in front of the decimal point. The decimal point is currently to the right of the last digit in $\\var{q2}$ and needs to move to between the first and second digits, that is $\\var{dec2}$. Count the places that the decimal point must jump and you get $\\var{pow2}$ places. That is,

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\\[\\var{q2}=\\var{dec2}\\times 10^{\\var{pow2}}\\]

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We have a positive $\\var{pow2}$ as the power because we need to make the number $\\var{dec2}$ bigger to get to $\\var{q2}$.

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