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Click 'Try another question like this one' if you need more practice.
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\nFactorise the numerator and denominator so that the binomials in both are the same.
\n${\\big(\\frac{\\var{n1}x}{\\var{d1}}\\big)\\big(\\frac{\\var{a1}x+\\var{a2}}{\\var{a1}x+\\var{a2}}\\big)}$
\nThe binomials cancel, leaving $x$ and its coefficient:
\n$\\big({\\simplify{{n1}/{d1}}}\\big)x$
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\nAs before, factorise the numerator and denominator. This time, however, you'll notice that the factors themselves are the same.
\n$\\big(\\frac{\\var{n2}n}{{\\var{n2}}n}\\big)\\big(\\frac{\\var{b1}n+\\var{b2}}{\\var{b3}n+\\var{b4}}\\big)$
\nThe factors cancel, leaving:
\n$\\big(\\frac{\\var{b1}n+\\var{b2}}{\\var{b3}n+\\var{b4}}\\big)$
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\nHere, the quadratic expression in the numerator needs to be factorised into the product of two binomials.
\n$\\frac{({\\simplify{x+{c1}}})({\\simplify{x+{c2}}})}{({\\simplify{x+{c1}}})}$
\nYou will notice that one of the binomials in the numerator is the same as the denominator, which means that they can be cancelled. This leaves the expression:
\n${\\simplify{x+{c2}}}$
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\nNote: Although the question may accept coefficients in their decimal forms, it would be more appropriate to keep them in their most simplified fraction forms.
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