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Part a)
\nGiven $\\var{a}x+\\var{b}=\\var{c}$, we can start by subtracting $\\var{b}$ from both sides to get $\\var{a}x = \\simplify{{c-b}}$.
\nDividing both sides by $\\var{a}$ gives us $x= \\simplify {{c-b}/{a}}$
\n\n
Part b)
We could start by subtracting $\\var{d}$ from both sides to get $-\\var{f}y = \\simplify{{g-d}}$.
\nOr we could first add $\\var{f}y $ to both sides to get $\\var{d} = \\var{g} + \\var{f}y$. This avoids needing to divide by a negative number.
\nEither way we should end up with $y= \\dfrac{\\simplify{{d- g}}}{\\var{f}}= \\simplify{{d-g}/{f}}$.
\n\n
\n
Part c)
\n$\\displaystyle{\\frac{z}{\\var{h}}}-\\var{j}=\\var{k}$
\n$\\displaystyle{\\frac{z}{\\var{h}}}=\\var{k+j}$
\n$z=\\var{ans3}$
\n\n\nPart d)
\n$\\displaystyle{\\frac{a-\\var{l}}{\\var{m}}}=\\var{n}$
\n$a-\\var{l}=\\var{n*m}$
\n$a=\\var{ans4}$
\nPart e)
\n$\\var{p}$$=$$\\var{q}(\\var{r}+b)$
\n$\\displaystyle{\\simplify{{p}/{q}}}$$=$$\\var{r}+b$
\n$\\displaystyle{\\simplify{{p-r*q}/{q}}}$$=$$b$
\n\n\nPart f)
\n$\\displaystyle{\\frac{\\var{s}w}{\\var{t}}}$$=$$\\var{u}$
\n$\\var{s}w$$=$$\\var{u*t}$
\n$w$$=$$\\displaystyle{\\simplify{{u*t}/{s}}}$
\n\n
For more help, check this video-
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$\\var{a}x+\\var{b}=\\var{c}$
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\nSubtract 3x from both sides of the equation: 2x - 6 = -8
\nAdd 6 to both sides of the equation: 2x = -2 or x= -1
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\nFor help on solving linear equations, check this video- https://www.youtube.com/watch?v=8j3kRdiRjPA
\nGive your answer as either an integer, a non-recurring decimal or a fraction
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