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Given th original formula the student enters the transformed formula

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{eqnline(a,b,x2,y2,v,sin0)}

The graph shows the functions, $y=sin(x)$ and $y=\\var{sin0}$

Calulate the solutions to the equation $sin(x)=\\var{sin0}$ in the range $-360 \\leqslant x \\leqslant 360$

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We know that the graph crosses the $x$-axis at both $(\\var{a},0)$ and $(\\var{b},0)$. Since this is a quadratic, we know our equations has two roots, and by the previous observation, they are at $\\var{a}$ and $\\var{b}$. Hence we can write our equation as $\\simplify{y=(x-{a})(x-{b})}$ which simplifies to $\\simplify{y=x^2-({a}+{b})x+({a}*{b})}$.

To find the coefficients of the turning point of the quadratic, we know the x-coordinate of the turning point will correspond to the solution to $dy/dx=0$. So we get $\\simplify{2x-({a}+{b})}=0$ hence $\\simplify{x=({a}+{b})/2}$. We substitute this value of x back into the equation of the quadratic to find the corresponding y-coordinate.

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\n\n// create the x-axis.\nvar xaxis = board.create('line',[[0,0],[1,0]], {strokeColor: 'black', fixed: true});\n\nvar xticks = board.create('ticks',[xaxis,60],{\n\n drawLabels: true,\n label: {offset: [-4, -10]},\n minorTicks: 0\n});\n\n\n// create the line.\n\n\nboard.create('line',[[x_min,sin0],[x_max,sin0]],{strokeColor:'red'});\n\n// create the y-axis\nvar yaxis = board.create('line',[[0,0],[0,1]], { strokeColor: 'black', fixed: true });\nvar yticks = board.create('ticks',[yaxis,1],{\ndrawLabels: true,\nlabel: {offset: [-20, 0]},\nminorTicks: 0\n});\n\n\n // PUT YOUR FUNCTION HERE\n\n// sin (x) in degrees\nboard.create('functiongraph',[function(x){ return Math.sin(x*(Math.PI/180));},x_min,x_max]);\n//board.create('functiongraph',[function(x){ return Math.sin(x*(Math.PI/180))+v;},-360,360],{ strokeColor: 'red'});\n//board.create('functiongraph',[function(x){ return Math.sin(x*(Math.PI/180))-(v+1);},-360,360],{ strokeColor: 'black'});\n//Change axis range from -360 tp +360 y from -8 to +8 \n\n//board.create('functiongraph',[function(x){ return Math.exp(x);},x_min,x_max]);\n//board.create('functiongraph',[function(x){ return Math.log(x);},x_min,x_max]);\n//board.create('functiongraph',[function(x){ return (x);},x_min,x_max]);\n\n\n//board.create('functiongraph',[function(x){ return (x-a)*(x-b);},-8,8]);\n//board.create('functiongraph',[function(x){ return (x-a)*(x-b)+v;},-8,8],{ strokeColor: 'red'});\n\n//board.create('functiongraph',[function(x){ return x*x;},-8,8]);\n//board.create('functiongraph',[function(x){ return x*x+v;},-8,8],{ strokeColor: 'red'});\n//board.create('functiongraph',[function(x){ return x*x-(v+1);},-8,8],{ strokeColor: 'black'});\n\n\n//board.create('functiongraph',[function(x){ return x*x;},-8,8]);\n//board.create('functiongraph',[function(x){ return (x-v)*(x-v);},-8,8],{ strokeColor: 'red'});\n//board.create('functiongraph',[function(x){ return (x+v+1)*(x+v+1);},-8,8],{ strokeColor: 'black'});\n\n//board.create('functiongraph',[function(x){ return x*x;},-8,8]);\n//board.create('functiongraph',[function(x){ return v*(x)*(x);},-8,8],{ strokeColor: 'red'});\n//board.create('functiongraph',[function(x){ return (1/v)*(x)*(x);},-8,8],{ strokeColor: 'black'});\n\n//board.create('functiongraph',[function(x){ return (x)*(x)+v;},-8,8]);\n//board.create('functiongraph',[function(x){ return -((x)*(x)+v);},-8,8],{ strokeColor: 'red'});\n//board.create('functiongraph',[function(x){ return -(x)*(x);},-8,8],{ strokeColor: 'black'});\n\n\n\n\n\n\nreturn div;"}}, "preamble": {"js": "", "css": ""}, "parts": [{"type": "gapfill", "useCustomName": false, "customName": "", "marks": 0, "scripts": {}, "customMarkingAlgorithm": "", "extendBaseMarkingAlgorithm": true, "unitTests": [], "showCorrectAnswer": true, "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "nextParts": [], "suggestGoingBack": false, "adaptiveMarkingPenalty": 0, "exploreObjective": null, "prompt": "

The smallest positive solution is give the solution to 1 decimal place.

$g(x)=\\;$[[0]]

You have not given your answer to the correct precision.

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Give the largest positive solution in the range correct to 1 decimal place.

$g(x)=\\;$[[0]]

You have not given your answer to the correct precision.

Give the smallest solution in the range correct to 1 decimal place.

$g(x)=\\;$[[0]]

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