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To find common ratio, simply divide one term by its predecessor.
\nTo find the $n$th term, multiply the first term a by the common ratio r to the power of n-1, ie ${a}{r^{n-1}}$
\nFormula for the sum of the first $n$ terms is where $r$ is the common ratio and $a$ is the first term
\nFormula for the infinite sum, providing $| r |<1$, is C
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", "expectedvariablenames": [], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "scripts": {}, "answer": "{t1}(1-(-1/{td})^{tsum})/(1+(1/{td}))", "marks": 1, "checkvariablenames": false, "checkingtype": "absdiff", "type": "jme"}, {"vsetrangepoints": 5, "prompt": "Find the exact sum to infinity of the series.
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\n$\\var{t1} - \\simplify{{t1}/{td}} + \\simplify{{t1}/{td}^2} - \\simplify{{t1}/{td}^3} +...$
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