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1) Voer de vraag zelf uit als leerling

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2) Randomiseer deze vraag. Vervang de concrete getalletjes door willekeurig getrokken variabelen, maar zorg dat de vraagstelling en modeloplossing nog mooi eruit zien.

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3) Controleer of de willekeurige getallen altijd even moeilijk zijn, of de randomisatie soms significant moeilijker is. Indien ze moeilijker is, beperk die gevallen bij Variable Testing.

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The function $f: y=2x^2+2x+c$ has $0$ as an extreme value.

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A quadratic function $f:y=ax^2+bx+c$ has a parabolic graph and reaches it extremal value at the vertex.

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The $x$-value of the vertex is found as $x=-\\frac{b}{2a}=-\\frac{2}{4}=-\\frac{1}{2}$.

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The extremal value itself is  given by $f(-\\frac{1}{2})=-\\frac{1}{2}+c$.  Since this must be equal to $0$, we find $-\\frac{1}{2}+c=0$, hence $c=\\frac{1}{2}$.

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Find $c$.

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