// Numbas version: exam_results_page_options {"name": "Interaction: enter domain with brackets", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "Interaction: enter domain with brackets", "tags": [], "metadata": {"description": "", "licence": "None specified"}, "statement": "

Find the domain of the function $f(x)=\\sqrt{\\frac{\\var{a}-x}{x+\\var{b}}}$.

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A square root is only defined for positive values, so we need to solve the inequality $g(x)=\\frac{\\var{a}-x}{x+\\var{b}}\\geq 0$.   We make a sign chart for the rational function $g$

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  1. domain is all real numbers except $\\var{-b}$;
  2. \n
  3. there is one zero at $\\var{a}$;
  4. \n
  5. there are 3 regions to consider: $x<\\var{-b}$, $\\var{-b}<x<\\var{a}$ and $\\var{a}<x$.  By evaluating the rational function at any point of a given region, we establish that it takes negative values on the first and the third region and positive values on the second.
  6. \n
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This results in the following sign chart:

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$x$$\\var{-b}$$\\var{a}$
$g(x)$$-$\\$+$0$-$
\n

So, the domain is given by $]\\var{-b},\\var{a}]$.

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The domain of this function is a single interval, namely: [[0]][[1]],[[2]][[3]]. 

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Instructions on entering your answer:

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You will need to fill out 4 parts of an interval: 

\n\n

Do not round values, enter a fraction if necessary.

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