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De functie $f: y=\\simplify{{a}*x^2+{b}*x+c}$ heeft $\\var{yv}$ als extreme waarde.
", "advice": "Een kwadratische functie $f:y=ax^2+bx+c$ heeft een parabolische grafiek en bereikt diens extreme waarde in de top/dal.
\nDe \\(x\\)-coördinaat vind je bij \\(x=-\\frac{b}{2a}=-\\frac{\\var{b}}{2\\cdot \\left(\\var{a}\\right)}=\\var{xv}\\).
\nDe extreme waarde zelf is dan \\(f(\\var{xv})=\\var{yv-c}+c\\). Aangezien dat gelijk moet zijn aan \\(\\var{yv}\\), vinden we de vergelijking \\(\\var{yv-c}+c=\\var{yv}\\), of dus \\(c=\\var{c}\\).
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\n$c=$[[0]]
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