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De functie $f: y=\\simplify{{a}*x^2+{b}*x+c}$ heeft $\\var{yv}$ als extreme waarde.

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Een kwadratische functie $f:y=ax^2+bx+c$ heeft een parabolische grafiek en bereikt diens extreme waarde in de top/dal.

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De \\(x\\)-coördinaat vind je bij \\(x=-\\frac{b}{2a}=-\\frac{\\var{b}}{2\\cdot \\left(\\var{a}\\right)}=\\var{xv}\\).

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De extreme waarde zelf is dan \\(f(\\var{xv})=\\var{yv-c}+c\\). Aangezien dat gelijk moet zijn aan \\(\\var{yv}\\), vinden we de vergelijking \\(\\var{yv-c}+c=\\var{yv}\\), of dus \\(c=\\var{c}\\).

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y-coordinate of the vertex

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coëfficiënt van kwadratische term van kwadratische functie

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coefficient van lineare term van kwadratische functie

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constante term van kwadratische functie

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x-coordinate of the vertex

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Vind $c$.

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$c=$[[0]]

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De \\(x\\)-coördinaat van het extremum is \\(\\frac{-b}{2a}\\). Hoe vind je dan de \\(y\\)-coördinaat? En wat betekent dat voor \\(c\\)?

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Je bent misschien een minteken vergeten in je berekening...?

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