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The idea here is to get all powers of x on one side of the equation, and all numbers on the other. Then, raise each side of the equation to an appropriate power, so that the value of x becomes clear.

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It may be useful to refamiliarise yourself with the laws of indices:

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$x^a \\times x^b = x^{a+b}$

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$x^a \\div x^b = x^{a-b}$

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$x^{-a} = \\frac{1}{x^a}$

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$(x^a)^b = x^{ab}$

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$(\\frac{x}{y})^a = \\frac{x^a}{y^a}$

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$x^\\frac{a}{b} = (\\sqrt[b]{x})^a$

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$x^0 = 1$

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$\\var{a}x^{\\var{c}} = \\var{d}$

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$\\var{d1}x^{\\var{c1}} = \\var{a1}$

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$x^3 + \\var{b2} = 0$

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$\\var{a3}x^{-1}=\\var{b3}$

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$x^{\\var{a4}}= \\var{c4}$

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Solve each of the following equations for x.

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Hint: Remember to do the same operation to both sides of the equation to keep it equivalent, with the idea being to get all powers of x on one side of the equation, and all numbers on the other. Then, raise each side of the equation to an appropriate power, so that the value of x becomes clear.

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Express answers either as an integer or as a fraction, and put the answer in the box. 

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