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Simplify each of these, giving your answer in its simplest form.

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$x^\\var{a} \\times x^\\var{b}$

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$p^\\var{c} \\times p^\\var{d}$

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$(\\var{a}k^\\var{b})^\\var{f}$

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$y^{\\simplify{1/{a}}} \\times y^{\\simplify{1/{b}}}$

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$c^\\var{a}$$c^\\var{b}$

\n

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$\\var{a}h^\\var{c}$$\\var{b}h^\\var{d}$

\n

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$(4d)^\\var{g}$$(2d)^\\var{h}$

\n

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$(6p^{-\\var{f}})^{\\var{g}}$$(9p^{-\\var{j}})^{\\var{h}}$

\n

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Simplifying indices.

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Recall the laws of indices to help solve the problems:

\n

$x^a \\times x^b = x^{a+b}$

\n

$x^a \\div x^b = x^{a-b}$

\n

$x^{-a} = \\frac{1}{x^a}$

\n

$(x^a)^b = x^{ab}$

\n

$(\\frac{x}{y})^a = \\frac{x^a}{y^a}$

\n

$x^\\frac{a}{b} = \\sqrt[b]{x^a}$

\n

$x^0 = 1$

\n

\n

Worked Solutions:

\n

Part a)

\n

$x^\\var{a} \\times x^\\var{b}=x^{(\\var{a}+\\var{b})}=x^{\\simplify{{a}+{b}}}$

\n

Part b)

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$p^\\var{c} \\times p^\\var{d}=p^{(\\var{c}+\\var{d})}=p^{\\simplify{{c}+{d}}}$

\n

Part c)

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For this question, recall that the exterior power is applied to both the coefficient and the variable within brackets.

\n

$(\\var{a}k^\\var{b})^\\var{f}=(\\var{a}^\\var{f}k^{\\var{b}\\times\\var{f}})=\\simplify{{a}^{f}}k^{\\simplify{{b}*{f}}}$

\n

Part d)

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$y^{\\simplify{1/{a}}} \\times y^{\\simplify{1/{b}}}=y^{\\frac{1}{\\var{a}}+\\frac{1}{\\var{b}}}=y^{\\simplify{{{a}+{b}}/{{a}*{b}}}}$

\n

Part e)

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$\\frac{c^{\\var{a}}}{c^{\\var{b}}}=c^{\\var{a}-\\var{b}}=c^{\\simplify{{a}-{b}}}$

\n

Part f)

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$\\frac{\\var{a}h^{\\var{c}}}{\\var{b}h^{\\var{d}}}=\\frac{\\var{a}}{\\var{b}}\\times h^{\\var{c}-\\var{d}}=\\simplify{{a}/{b}}h^{\\simplify{{c}-{d}}}$

\n

Part g)

\n

$\\frac{({4d})^{\\var{g}}}{({2d})^{\\var{h}}}=\\frac{4^{\\var{g}}{d}^{\\var{g}}}{2^{\\var{h}}{d}^{\\var{h}}}=\\frac{\\simplify{4^{{g}}}{d}^{\\var{g}}}{\\simplify{2^{{h}}}{d}^{\\var{h}}}=\\simplify{{4^{g}}/{2^{h}}}d^{\\var{g}-\\var{h}}=\\simplify{{4^{g}}/{2^{h}}}d^{\\simplify{{g}-{h}}}$

\n

Part h)

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$\\frac{({6p^{-\\var{f}}})^{\\var{g}}}{({9p^{-\\var{j}}})^{\\var{h}}}=\\frac{6^{\\var{g}}{p}^{-\\var{f}\\times\\var{g}}}{9^{\\var{h}}{p}^{-\\var{j}\\times\\var{h}}}=\\left(\\frac{\\simplify{6^{g}}}{\\simplify{9^{h}}}\\right)\\times \\frac{p^{\\simplify{-{f}*{g}}}}{p^{\\simplify{-{j}*{h}}}}=\\simplify{{6^{g}}/{9^{h}}}\\times p^{\\simplify{-{f}*{g}}-\\simplify{-{j}*{h}}}=\\simplify{{6^{g}}/{9^{h}}}p^{\\simplify{{-{f}*{g}}-{-{j}*{h}}}}$

\n

 

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