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start by multiplying both sides by the denominator
\nfor example if you have $V=\\frac{5S}{S+12}$ then multiply both sides by $(S+12)$
\nthis gives: $V(S+12)=\\frac{5S}{S+12} (S+12) $
\nthe (S+12) term on the right hand side cancels out to give: $V(S+12)=5S$
\nnow expand out the brackets: $VS+12V=5S$
\nthen collect the like terms, you want to get all the terms with S in them onto one side, so subtract VS from both sides:
\n$VS-VS+12V=5S-VS$
\nthis becomes $12V=5S-VS$
\nnow you can factorise the right hand side: $12V=S(5-V)$
\nthen divide both sides by (5-V) to leave S on its own: $\\frac{12V}{5-V}=S$
\n", "rulesets": {}, "parts": [{"prompt": "Rearrange the following equation to make S the subject.
\n\n$ V=\\frac{\\var{a}S}{S+\\var{b}}$
\n\nto write a fraction you type (numerator)/(denominator)
\nS=[[0]]
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", "licence": "Creative Commons Attribution 4.0 International"}, "type": "question", "contributors": [{"name": "Nigel Atkins", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/275/"}]}]}], "contributors": [{"name": "Nigel Atkins", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/275/"}]}