// Numbas version: finer_feedback_settings {"name": "10e. Solving (x+a)/b=c/(x+d)", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "10e. Solving (x+a)/b=c/(x+d)", "tags": [], "metadata": {"description": "

Solving equations involving algebraic fractions which simplify into quadratics

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Solve the following equation for $x$.

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\\[\\simplify{(x+{a})/{b}}=\\simplify{{c}/(x+{d})}\\]

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First multiply through by $\\var{b}$ and $\\simplify{x+{d}}$ and re-arrange to get 

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\\[\\simplify{x^2+{xCoff}x+{Const}=0}\\]

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To solve a quadratic equation of the form \\[ x^2+bx+c=0\\] by factorisation, we want to factorise the equation into the form \\[(x+p)(x+q)=0,\\] where $p+q=b$ and $p \\times q = c$. 

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Hence, for the equation \\[\\simplify{x^2+{xCoff}x+{Const}=0}, \\]

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this can be factorised to \\[\\simplify{(x+{x1})(x+{x2})=0}.\\] This equation is satisfied when either \\[\\simplify{x+{x1}=0} \\quad \\text{or} \\quad \\simplify{x+{x2}=0}, \\] which implies the solutions to this quadratic equation are \\[ \\simplify{x={-x1}} \\quad \\text{and} \\quad \\simplify{x={-x2}} .\\]

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Use this link to find resources to help you revise how to solve quadratic equations.

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x=[[0]]

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x=[[1]]

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