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Solving factorised quadratics with leading coefficient NOT 1

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Solve the following equation for $x$.

\n

\\[(\\simplify{{a}x+{c}})(\\simplify{{b}x+{d}})=0\\]

\n

Give your answers as fractins or intergers as appropriate.

", "advice": "

This equation is zero when either $(\\simplify{{a}x+{c}})=0$ or $(\\simplify{{b}x+{d}})=0$. We can re-arrange each equation to get the solutions

\n

\\[\\simplify[fractionNumbers]{x={-x1}},\\ \\simplify[fractionNumbers]{x={-x2}}.\\]

\n

Use this link to find resources to help you revise how to solve quadratic equations.

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x=[[0]]

\n

x=[[1]]

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