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In this question we're asked to find the value of the term $a_{\\var{r3}}$ (when $i={\\var{r3}}$).
\nGiven the sum definition for this geometric series provided in the question statement, the formula for the $i^{th}$ term would be:
\n$a_i=a_0r^i$ $_{(..II)}$ where $a_0$ is the first term of the series and $r$ is the common ratio.
\nSubstituting the given $i$ we have:
\n$a_\\var{r3}=a_0r^{\\var{r3}}$ $_{(..III)}$
\nBefore evaluating this, however, we need to find the values of $r$ and $a_0$.
\n\nFinding $r$:
\nTo find the common ratio $r$, we can first divide term $a_\\var{r2}$ by term $a_\\var{r1}$.
\n$\\left(\\frac{\\simplify{{t1}/{td}^{r2}}}{\\simplify{{t1}/{td}^{r1}}}\\right)=\\simplify{{{t1}*{td}^{r1}}/{{t1}*{td}^{r2}}}$
\nAlgebraically speaking, this is the same as:
\n$\\left(\\frac{a_0r^{\\var{r2}}}{a_0r^{\\var{r1}}}\\right)=r^{\\simplify{{r2}-{r1}}}$
\n$\\therefore\\;\\;\\;r^{\\simplify{{r2}-{r1}}}=\\simplify{{{t1}*{td}^{r1}}/{{t1}*{td}^{r2}}}$
\n$r$ is then found by taking the appropriate root:
\n$r=\\sqrt[\\simplify{{r2}-{r1}}]{\\simplify{{{t1}*{td}^{r1}}/{{t1}*{td}^{r2}}}}=\\simplify{1/{td}}$
\nWhich leaves,
\n$r=\\simplify{1/{td}}$
\n\n
Finding $a_0$:
\nThe formula $_{(II)}$ is first rearranged in terms of $a_0$:
\n$a_i=a_0r^{i}$ $\\therefore\\;\\;\\;a_0=\\left(\\frac{a_i}{r^{i}}\\right)$
\nWe can then substitute in the value of $r$, as well as either of the terms provided in the question statement.
\nFor example, for $a_i=a_\\var{r1}=\\simplify{{t1}/{td}^{r1}}$:
\n$a_0=\\left(\\frac{\\simplify{{t1}/{td}^{r1}}}{\\left(\\simplify{1/{td}}\\right)^{\\var{r1}}}\\right)=\\left(\\frac{\\simplify{{t1}/{td}^{r1}}}{\\left(\\simplify{1/{td}}\\right)^{\\var{r1}}}\\right)=\\simplify{{t1}/{td}^{r1}}\\times\\var{td}^{\\var{r1}}=\\var{t1}$
\n\nFinally, for $a_\\var{r3}$:
\nThese values can now be substituted into $_{(III)}$ and simplified:
\n$a_\\var{r3}=\\var{t1}(\\simplify{1/{td}})^{\\var{r3}}=\\simplify{{t1}/{{td}^{r3}}}$
", "rulesets": {}, "parts": [{"vsetrangepoints": 5, "prompt": "Assuming the common ratio $r$ is positive, what is the value of the term $a_{\\var{r3}}$ (when $i={\\var{r3}}$)?
", "expectedvariablenames": [], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "answersimplification": "all", "scripts": {}, "answer": "{t1}/{td}^{r3}", "marks": 1, "checkvariablenames": false, "checkingtype": "absdiff", "type": "jme"}], "extensions": [], "statement": "We are given a geometric series whose sum is defined by:
\n$\\displaystyle\\sum\\limits_{i=0}^na_0r^i=\\displaystyle\\sum\\limits_{i=0}^na_i$ $_{..(I)}$
\nWhen $i=\\var{r1}$, the term is calculated to be: $a_{\\var{r1}}=\\simplify{{t1}/{td}^{r1}}$
\nSimilarly, when $i=\\var{r2}$, the term is calculated to be: $a_{\\var{r2}}=\\simplify{{t1}/{td}^{r2}}$
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