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In this question we're asked to find the value of the term $a_{\\var{r3}}$ (when $i={\\var{r3}}$).

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Given the sum definition for this geometric series provided in the question statement, the formula for the $i^{th}$ term would be:

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$a_i=a_0r^i$ $_{(..II)}$  where $a_0$ is the first term of the series and $r$ is the common ratio.

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Substituting the given $i$ we have:

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$a_\\var{r3}=a_0r^{\\var{r3}}$ $_{(..III)}$

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Before evaluating this, however, we need to find the values of $r$ and $a_0$.

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Finding $r$:

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To find the common ratio $r$, we can first divide term $a_\\var{r2}$ by term $a_\\var{r1}$.

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$\\left(\\frac{\\simplify{{t1}/{td}^{r2}}}{\\simplify{{t1}/{td}^{r1}}}\\right)=\\simplify{{{t1}*{td}^{r1}}/{{t1}*{td}^{r2}}}$

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Algebraically speaking, this is the same as:

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$\\left(\\frac{a_0r^{\\var{r2}}}{a_0r^{\\var{r1}}}\\right)=r^{\\simplify{{r2}-{r1}}}$

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$\\therefore\\;\\;\\;r^{\\simplify{{r2}-{r1}}}=\\simplify{{{t1}*{td}^{r1}}/{{t1}*{td}^{r2}}}$

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$r$ is then found by taking the appropriate root:

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$r=\\sqrt[\\simplify{{r2}-{r1}}]{\\simplify{{{t1}*{td}^{r1}}/{{t1}*{td}^{r2}}}}=\\simplify{1/{td}}$

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Which leaves,

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$r=\\simplify{1/{td}}$

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Finding $a_0$:

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The formula $_{(II)}$ is first rearranged in terms of $a_0$:

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$a_i=a_0r^{i}$    $\\therefore\\;\\;\\;a_0=\\left(\\frac{a_i}{r^{i}}\\right)$

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We can then substitute in the value of $r$, as well as either of the terms provided in the question statement.

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For example, for $a_i=a_\\var{r1}=\\simplify{{t1}/{td}^{r1}}$:

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$a_0=\\left(\\frac{\\simplify{{t1}/{td}^{r1}}}{\\left(\\simplify{1/{td}}\\right)^{\\var{r1}}}\\right)=\\left(\\frac{\\simplify{{t1}/{td}^{r1}}}{\\left(\\simplify{1/{td}}\\right)^{\\var{r1}}}\\right)=\\simplify{{t1}/{td}^{r1}}\\times\\var{td}^{\\var{r1}}=\\var{t1}$

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Finally, for $a_\\var{r3}$:

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These values can now be substituted into $_{(III)}$ and simplified:

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$a_\\var{r3}=\\var{t1}(\\simplify{1/{td}})^{\\var{r3}}=\\simplify{{t1}/{{td}^{r3}}}$

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Assuming the common ratio $r$ is positive, what is the value of the term $a_{\\var{r3}}$ (when $i={\\var{r3}}$)?

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We are given a geometric series whose sum is defined by:

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$\\displaystyle\\sum\\limits_{i=0}^na_0r^i=\\displaystyle\\sum\\limits_{i=0}^na_i$ $_{..(I)}$

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When $i=\\var{r1}$, the term is calculated to be: $a_{\\var{r1}}=\\simplify{{t1}/{td}^{r1}}$

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Similarly, when $i=\\var{r2}$, the term is calculated to be: $a_{\\var{r2}}=\\simplify{{t1}/{td}^{r2}}$

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