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Learn from your mistakes and have another attempt by clicking on 'Try another question like this one' until you get full marks.

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$\\displaystyle\\frac{\\var{a}}{\\var{b}}+\\frac{\\var{c}}{\\var{b}}=$[[0]]

$\\displaystyle\\frac{\\var{d}}{\\var{c}}-\\frac{\\var{a}}{\\var{c}}=$[[1]]

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Add the numerators, keep the denominator unchanged.

Since the deniminator is common in these fractions, it can easily be calculated as seen in this example:

\\[\\frac{2}{3}+\\frac{5}{3}=\\frac{2+5}{3}=\\frac{7}{3}\\]

The same rule goes for subtracting fractions:

\\[\\frac{7}{4}-\\frac{3}{4}=\\frac{7-3}{4}=\\frac{4}{4}=1\\]

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Calculate

$\\displaystyle\\simplify{{h}/{f}-{j}/{g}}=$ [[0]]

$\\displaystyle \\frac{\\var{a}}{\\var{d}}+\\var{f}=$ [[1]]

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Expand the fraction to get a common denominator. Now you do the same as in the previous task.

For example: $\\frac{5}{4}+\\frac{3}{8}$ expands the first fraction into $\\frac{10}{8}$ (by multiplying the numerator and denominator by 2), so that both fractions has the common denominator of 8.

\\[\\frac{5}{4}+\\frac{3}{8}=\\frac{5\\cdot 2}{4\\cdot 2}+\\frac{3}{8}=\\frac{10}{8}+\\frac{3}{8}=\\frac{13}{8}\\]

Sometimes we need to expand all parts to get a common denominator, for example if we need to calculate $\\frac{5}{4}-\\frac{2}{3}$. Here, we find 12 as the common denominator and calculates as such:

\\[\\frac{5}{4}-\\frac{2}{3}=\\frac{5\\cdot 3}{4\\cdot 3}-\\frac{2\\cdot 4}{3\\cdot 4}=\\frac{15}{12}-\\frac{8}{12}=\\frac{7}{12}\\]

Try to keep the common denomintar as low as possible.

NB! Keep in mind that integers may be written as a fraction with the denominator 1. Example: $3=\\frac{3}{1}$.

Calculate and give your answer as a fraction or an integer. Use / as the fractionline, for example $\\frac{2}{3}$ is written as 2/3.

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Add, subtract, multiply and divide numerical fractions.

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