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$y=\\sin(\\var{c[0]}x)$
\n$\\frac{dy}{dx}=$ [[0]]
\nEjemplo de respuesta: si la respuesta es
$-2\\sin{2x}$, digite -2sin(2x) en la barra de respuesta.
Como en estas funciones trigonométricas se tiene un ángulo que no es $x$, hay que considerar la regla de la cadena para calcular su derivada.
\nregla de la cadena: $\\dfrac{d}{dx}[f(u)]=f'(u) \\times u'$; $u$ función de $x$ y con:
\nfunción externa: $f(u)=\\sin{u}$
\nfunción interna: $u=\\var{c[0]}x$
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\n$\\frac{dy}{dx}=$ [[0]]
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\n$\\frac{dy}{dx}=$ [[0]]
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\n$\\frac{dy}{dx}=$ [[0]]
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\n$\\frac{dy}{dx}=$ [[0]]
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\n$\\frac{dy}{dx}=$ [[0]]
", "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "steps": [{"prompt": "A diferencia de los ejercicios anteriores, la función externa no es la función trigonometrica, la externa se entiende algebraica y la interna trigonométrica:
\nregla de la cadena: $\\dfrac{d}{dx}[f(u)]=f'(u) \\times u'$; $u$ función de $x$ y con:
\nfunción externa: $f(u)=u^\\var{p[0]}$
\nfunción interna: $u=\\tan{x}$
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