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Si $u$ y $v$ son funciones derivables de $x$, entonces se cumple que:
\\[\\simplify[std]{Diff(u/v,x,1) = (v * Diff(u,x,1) - u * Diff(v,x,1))/v^2}\\]

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Para el ejemplo, tenemos que:

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\\[\\simplify[dPoly]{u = {a} * x + {b}}\\Rightarrow \\simplify{Diff(u,x,1) = {a}}\\]

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\\[\\simplify[dPoly]{v = Sqrt({c} * x + {d})} \\Rightarrow \\simplify[dPoly]{Diff(v,x,1) = {c} / (2 * Sqrt({c} * x + {d}))}\\]

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Ahora sustituimos en la fórmula del cociente:

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\\[\\simplify[dPoly]{Diff(f,x,1) = ({a} * Sqrt({c} * x + {d}) -(({a} * x + {b}) * Diff(v,x,1))) / ({c} * x + {d}) = ({a} * Sqrt({c} * x + {d}) -(({c} * ({a} * x + {b})) / (2 * Sqrt({c} * x + {d})))) / ({c} * x + {d}) = ({2 * a} * ({c} * x + {d}) -({c} * ({a} * x + {b}))) / (2 * ({c} * x + {d}) ^ (3 / 2)) = ({a * c} * x + {2 * a * d -(c * b)}) / (2 * ({c} * x + {d}) ^ (3 / 2))}\\]

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Con lo cual se concluye que  \\[\\simplify[dPoly]{g(x) = {a * c} * x + {2 * a * d -(c * b)}}\\].

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\\[\\simplify[dPoly]{f(x) = ({a} * x + {b}) / Sqrt({c} * x + {d})}\\]

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La derivada tiene la forma:  \\[\\simplify[dPoly]{Diff(f,x,1) = g(x) / (2 * ({c} * x + {d}) ^ (3 / 2))}\\]

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Cuál es el polinomio $g(x)$, con el que la derivada es la correcta.

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$g(x)=\\;$[[0]]

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Ejemplo de respuesta: escriba −21x^2−12x+7, si la respuesta es $−21x^2−12x+7$

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Si $u$ y $v$ son funciones derivables de $x$, entonces se cumple que:
\\[\\simplify[std]{Diff(u/v,x,1) = (v * Diff(u,x,1) - u * Diff(v,x,1))/v^2}\\]

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con:

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$u=\\simplify[std]{{a} * x+{b}}$

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$v=\\simplify[std]{Sqrt({c} * x + {d})}$

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Calcular la derivada de la función

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Differentiate $f(x) = (a x + b)/ \\sqrt{c x + d}$ and find $g(x)$ such that $ f^{\\prime}(x) = g(x)/ (2(c x + d)^{3/2})$.

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