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Determinar la ecuación de la recta tangente a la curva $\\simplify{y={a[0]}x^2+{b[0]}x+{c[0]}}$ en el punto en el que cruza el eje $y$.

$\\frac{dy}{dx}=$ [[0]]

Por tanto, la pendiente de la tangente donde $x=0$ es [[1]]

Para la función, si $x=0$, entonces $y=$ [[2]]

Finalmente, la ecuación de la recta tangente es: $y=$ [[3]]

Determinar la ecuación de la recta normal a la curva $\\simplify{y={a[1]}x^2+{b[1]}x+{c[1]}}$ en el punto donde $x=\\var{d}$.

$\\frac{dy}{dx}=$ [[0]]

El valor de la derivada cuando $x=\\var{d}$ es [[1]]

El valor de la pendiente de la recta normal cuando $x=\\var{d}$ es [[4]]

La coordenada $y$ en la función cuando $x=\\var{d}$, $y=$ [[2]]

Finalmente, la ecuación de la normal es, $y=$ [[3]]

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Using differentiation to find the tangent and normal to a line at a given point

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