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[Maximum mark: 6]
\nAn arithmetic sequence has u_1 = {u_1}, u_2 = {u_2}, u_3 = {u_3}
\n(a) Find the common difference, d [2]
\n(b) Find u_8 [2]
\n(c) Find S_8 [2]
", "advice": "(a) The common difference is
\nd = u_2 - u_1
\nd = {u_2} - {u_1}
\nd = {u_2 - u_1}
\n(b) Using the nth term formula u_n = u_1 + (n - 1)d with n = {n}, we get
\nu_8 = u_1 + ({n} - 1)d
\nu_8 = {u_1} + (8 - 1)({d})
\nu_8 = {u_1 + (8 - 1)(d)}
\nc) Using the sum of n terms formula S_n = (n/2)(u_1 + u_n) with n = {n}, we obtain
\nS_8 = ({n}/2)({u_1} + {u_8})
\nS_8 = {(n/2)(u_1 + (u_8))}
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