// Numbas version: finer_feedback_settings {"name": "32.b Division in standard form", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "32.b Division in standard form", "tags": ["converting", "scientific notation", "standard form"], "metadata": {"description": "
Convert numbers between 0 and 1 intro standard form/scientific notation.
", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "Calculate the following expression and write the answer in standard form.
", "advice": "{advice}
\nUse this link to find some resources which will help you revise this topic.
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\\n\\\\[\\\\left(\\\\var{Num1}\\\\times 10^\\\\var{Pow1}\\\\right)\\\\div\\\\left(\\\\var{Num2}\\\\times 10^\\\\var{Pow2}\\\\right)\\\\]
\\nas the fraction
\\n\\\\[\\\\frac{\\\\var{Num1}\\\\times 10^\\\\var{Pow1}}{\\\\var{Num2}\\\\times 10^\\\\var{Pow2}}\\\\]
\\nat which point there are different ways to cancel down to one number in standard form. One option is to convert both numbers out of standard form but this can often be very messy. Alternatively we can simply divide $\\\\var{Num1}$ by $\\\\var{Num2}$ and $10^\\\\var{Pow1}$ by $10^\\\\var{Pow2}$ which gives us
\\n\\\\[\\\\frac{\\\\var{Num1}\\\\times 10^\\\\var{Pow1}}{\\\\var{Num2}\\\\times 10^\\\\var{Pow2}}=\\\\var{Num1/Num2}\\\\times 10^\\\\var{Pow1-Pow2}.\\\\]
\\nSince this is not in standard form we need to decrease the power by $1$ and multiply the number in front by $10$ to get a final answer of
\\n\\\\[\\\\var{Num1/Num2*10}\\\\times 10^\\\\var{Pow1-Pow2-1}.\\\\]
\\n\\nAnother option if you are not comfortable with dividing $\\\\var{Num1}$ by $\\\\var{Num2}$ is to multiply $\\\\var{Num1}$ by $10$ and decrease the power $\\\\var{Pow1}$ by $1$. This makes the division slightly easier as we get
\\n\\\\[\\\\frac{\\\\var{Num1}\\\\times 10^\\\\var{Pow1}}{\\\\var{Num2}\\\\times 10^\\\\var{Pow2}}=\\\\frac{\\\\var{Num1*10}\\\\times 10^\\\\var{Pow1-1}}{\\\\var{Num2}\\\\times 10^\\\\var{Pow2}}=\\\\var{Num1/Num2*10}\\\\times10^\\\\var{Pow1-Pow2-1}.\\\\]
\\nThis is already in standard form so we are done.
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\\n\\\\[\\\\left(\\\\var{Num1}\\\\times 10^\\\\var{Pow1}\\\\right)\\\\div\\\\left(\\\\var{Num2}\\\\times 10^\\\\var{Pow2}\\\\right)\\\\]
\\nas the fraction
\\n\\\\[\\\\frac{\\\\var{Num1}\\\\times 10^\\\\var{Pow1}}{\\\\var{Num2}\\\\times 10^\\\\var{Pow2}}\\\\]
\\nand then we can cancel the terms which are easiest to divide. In this case it is easiest to divide $\\\\var{Num1}$ by $\\\\var{Num2}$ and $10^\\\\var{Pow1}$ by $10^\\\\var{Pow2}$ which gives us
\\n\\\\[\\\\frac{\\\\var{Num1}\\\\times 10^\\\\var{Pow1}}{\\\\var{Num2}\\\\times 10^\\\\var{Pow2}}=\\\\var{Num1/Num2}\\\\times 10^\\\\var{Pow1-Pow2}.\\\\]
\\nSince this is already in standard form then we are done.
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