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Find the sum of the first n terms of a Geometric progression

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If the ratio between successive pairs of terms is a constant then the series under examination is a geometric progression.

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Ths first term is \\(a\\) and the common ratio is \\(r\\).

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The formula for the sum of the first \\(n\\) terms of the series is given by:    \\(S_n=\\frac{a(1-r^{n})}{1-r}\\)

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In this example \\(a=\\var{a}\\),   \\(r = \\frac{\\simplify{{a}*{r}}}{\\var{a}}=\\var{r}\\)  and  \\(n = \\var{n}\\)

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\\(S_\\var{n}=\\frac{\\var{a}(1-(\\var{r})^{\\var{n}})}{1-\\var{r}}\\)

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\\(S_\\var{n}=\\frac{\\var{a}*(\\simplify{1-{r}^{n}})}{\\simplify{1-{r}}}\\)

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\\(S_\\var{n}=\\frac{\\simplify{{a}*(1-{r}^{n})}}{\\simplify{1-{r}}}\\)

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\\(S_\\var{n}=\\var{s}\\)

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Calculate the sum of the first \\(\\var{n}\\) terms of the series.

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\\(S_\\var{n}=\\) [[0]]

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The first three terms of a series are given by:  

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\\(\\var{a} + \\simplify{{a}*{r}} + \\simplify{{a}*{r}^2}\\,+ \\, ...........\\)

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