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Here are the ages of 7 people:

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{a1}, {a2}, {a3}, {a4}, {a5}, {a6}, {a7}.

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First we should order our list of ages from smallest to largest:

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$\\var{list[0]}, \\var{list[1]}, \\var{list[2]}, \\var{list[3]}, \\var{list[4]}, \\var{list[5]}, \\var{list[6]}$.

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a)

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To find the range of ages we must subtract the smallest age from the largest age,

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$\\var{max(list)} - \\var{min(list)} = \\var{range}$.

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Hence, the range is $\\var{range}$.

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b) 

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To calculate the interquartile range we subtract the lower quartile from the upper quartile.

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To calculate the lower quartile:

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Since we have an odd number of ages we had one to the total and divide by 4,

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$\\frac{7+1}{4} = \\frac{8}{4} = 2.$

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So we are looking for the $2^{nd}$ value in our list which is $\\var{lq}$.

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Hence the lower quartile is $\\var{lq}$.

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To find the upper quartile:

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We still add one to the number of ages because this number is odd and then we find $75$% of it,

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$\\frac{3\\times(7+1)}{4} = \\frac{3\\times8}{4} = \\frac{24}{4} = 6.$

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So we are looking for the $6^{th}$ value in our list which is $\\var{uq}$.

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Hence the lower quartile is $\\var{uq}$.

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Now we can calculate the interquartile range by subtracting the lower quartile from the upper quartile,

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$\\var{uq}-\\var{lq} = \\var{iqr}.$

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Age 1

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Age 2

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Age 3

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Age 4

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Age 5

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Age 6

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Age 7

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Ages in ascending order

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Range

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Lower quartile

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Upper quartile

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Interquartile range

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Work out the range of ages.

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Work out the interquartile range of the ages.

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