// Numbas version: exam_results_page_options {"name": "Application 2: Differential equation with an irreducible quadratic factor: X(s)", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"metadata": {"description": "

Solve a Differential equation with an irreducible quadratic factor 

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A metal plate attached to a stiff spring and immersed in viscous oil is in motion and its position \\(x(t)\\) at time \\(t\\) satisfies the differential equation

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     \\(\\frac{d^2x}{dt^2}+\\simplify{2*{a1}}\\frac{dx}{dt}+\\simplify{{a1}*{a1}+{a2}*{a2}}x(t)=\\var{R}\\)  

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The plate is in moving at \\(\\var{b2}cm/s\\) and is initially at a height of \\(\\var{b1}cm\\) so that, \\(x(0)=\\var{b1} \\,\\, and \\,\\,  x'(0)=\\var{b2}\\)

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The solution to the differential equation is given by

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     \\(x(t)=A+Be^{-\\var{a1}t}cos(\\var{a2}t)+Ce^{-\\var{a1}t}sin(\\var{a2}t)\\)

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.

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Enter the value for \\(A\\) as an exact fraction.            \\(A=\\) [[0]]

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Enter the value for \\(B\\) as an exact fraction.            \\(B=\\)  [[1]]

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Enter the value for \\(C\\) as an exact fraction.            \\(C=\\)  [[2]]

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 \\(\\frac{d^2x}{dt^2}+\\simplify{2*{a1}}\\frac{dx}{dt}+\\simplify{{a1}*{a1}+{a2}*{a2}}x(t)=\\var{R}\\)  where \\(x(0)=\\var{b1} \\,\\, and \\,\\,  x'(0)=\\var{b2}\\)

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The Laplace transform of this is given by:

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\\(s^2X(s)-\\var{b1}s-\\var{b2}+\\simplify{2*{a1}}(sX(s)-\\var{b1})+\\simplify{{a1}*{a1}+{a2}*{a2}}X(s)=\\frac{\\var{R}}{s}\\)

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Gathering only \\(X(s)\\) terms on the left hand side and factoring gives:

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\\(s^2X(s)+\\simplify{2*{a1}}sX(s)+\\simplify{{a1}^2+{a2}^2}X(s)=\\frac{\\var{R}}{s}+\\var{b1}s+\\simplify{{b2}+2*{a1}*{b1}}\\)

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\\((s^2+\\simplify{2*{a1}}s+\\simplify{{a1}^2+{a2}^2})X(s)=\\frac{\\var{b1}s^2+\\simplify{{b2}+2*{a1}*{b1}}s+\\var{R}}{s}\\)

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\\(X(s)=\\frac{\\var{b1}s^2+\\simplify{{b2}+2*{a1}*{b1}}s+\\var{R}}{s(s^2+\\simplify{2*{a1}}s+\\simplify{{a1}^2+{a2}^2})}\\)

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\\(X(s)=\\frac{A}{s}+\\frac{Bs+c}{(s^2+\\simplify{2*{a1}}s+\\simplify{{a1}^2+{a2}^2})}\\)

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\\(\\var{b1}s^2+\\simplify{{b2}+2*{a1}*{b1}}s+\\var{R}=A(s^2+\\simplify{2*{a1}}s+\\simplify{{a1}^2+{a2}^2})+Bs^2+cs\\)

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Let \\(s=0\\)

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\\(\\var{R}=A(\\simplify{{a1}^2+{a2}^2})\\)

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\\(A=\\simplify{{R}/({a1}^2+{a2}^2)}\\)

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Compare the coefficients of \\(s^2\\)   

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\\(\\var{b1}=A+B\\)

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\\(B=\\var{b1}-\\simplify{{R}/({a1}^2+{a2}^2)}=\\simplify{({b1}*({a1}^2+{a2}^2)-{R})/({a1}^2+{a2}^2)}\\)

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Compare the coefficients of \\(s\\)

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\\(\\simplify{{b2}+2*{a1}*{b1}}=\\simplify{2*{a1}}A+c\\)

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\\(c=\\simplify{{b2}+2*{a1}*{b1}}-\\simplify{2*{a1}}A\\)

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\\(c=\\simplify{(({b2}+2*{a1}*{b1})*({a1}^2+{a2}^2)-2*{a1}*{R})/({a1}^2+{a2}^2)}\\)

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\\(X(s)=\\frac{\\simplify{{R}/({a1}^2+{a2}^2)}}{s}+\\frac{\\simplify{({b1}*({a1}^2+{a2}^2)-{R})/({a1}^2+{a2}^2)}s+\\simplify{(({b2}+2*{a1}*{b1})*({a1}^2+{a2}^2)-2*{a1}*{R})/({a1}^2+{a2}^2)}}{s^2+\\simplify{2*{a1}}s+\\simplify{{a1}^2+{a2}^2}}\\)

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\\(X(s)=\\frac{\\simplify{{R}/({a1}^2+{a2}^2)}}{s}+\\frac{\\frac{\\simplify{({b1}*({a1}^2+{a2}^2)-{R})}}{\\simplify{({a1}^2+{a2}^2)}}(s+\\var{a1})}{(s+\\var{a1})^2+\\var{a2}^2}+\\frac{\\simplify{(({b2}+2*{a1}*{b1})*({a1}^2+{a2}^2)-2*{a1}*{R}-{a1}*({b1}*({a1}^2+{a2}^2)-{R}))/({a1}^2+{a2}^2)}}{(s+\\var{a1})^2+\\var{a2}^2}\\)

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\\(x(t)=\\simplify{{R}/({a1}^2+{a2}^2)}+\\simplify{({b1}*({a1}^2+{a2}^2)-{R})/({a1}^2+{a2}^2)}e^{-\\var{a1}t}cos(\\var{a2}t)+\\simplify{(({b2}+2*{a1}*{b1})*({a1}^2+{a2}^2)-2*{a1}*{R}-{a1}*({b1}*({a1}^2+{a2}^2)-{R}))/({a2}*({a1}^2+{a2}^2))}e^{-\\var{a1}t}sin(\\var{a2}t)\\)

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