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One-step equation solving - just adding.
", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "Solve the following equation for $\\var{Letter}$.
\n\\[\\simplify{{Letter}+{Num1}}=\\var{Num2}.\\]
", "advice": "To solve $\\simplify{{Letter}+{Num1}}=\\var{Num2}$ we need to get the $\\var{Letter}$ by itself. We need to get rid of the $\\var{Num1}$ so if we add $\\var{-Num1}$ to both sides then we will get the $\\var{Letter}$ by itself. This gives us
\n\\[\\simplify{{Letter}+{Num1}}=\\var{Num2}\\]
\n\\[\\simplify[basic]{{Letter}+{Num1}+{-Num1}}=\\simplify[basic]{{Num2}+{-Num1}}\\]
\n\\[\\var{Letter}+0=\\var{Num2-Num1}\\]
\n\\[\\var{Letter}=\\var{Num2-Num1}.\\]
\n
Use this link to find resources to help you revise how to solve linear equations
$\\var{Letter}=$
", "minValue": "{Num2-Num1}", "maxValue": "{Num2-Num1}", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always", "contributors": [{"name": "Mash Sheffield", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4679/"}, {"name": "Andrew Neate", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/21832/"}], "resources": []}]}], "contributors": [{"name": "Mash Sheffield", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4679/"}, {"name": "Andrew Neate", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/21832/"}]}