// Numbas version: finer_feedback_settings {"name": "37.c Simple linear equations 3 - Just multiplication", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"name": "37.c Simple linear equations 3 - Just multiplication", "tags": [], "metadata": {"description": "
One step equations - just multiplication.
", "licence": "Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International"}, "statement": "Solve the following equation for $\\var{Letter}$.
\n\\[\\frac{\\var{Letter}}{\\var{Num1}}=\\var{Num2}.\\]
", "advice": "To solve $\\frac{\\var{Letter}}{\\var{Num1}}=\\var{Num2}$ we need to get the $\\var{Letter}$ by itself. We need to get rid of the $\\var{Num1}$ so if we multiply by $\\var{Num1}$ on both sides then we will get the $\\var{Letter}$ by itself. This gives us
\n\\[\\frac{\\var{Letter}}{\\var{Num1}}=\\var{Num2}\\]
\n\\[\\frac{\\var{Letter}}{\\var{Num1}}\\times\\var{Num1}=\\var{Num2}\\times\\var{Num1}\\]
\n\\[\\var{Letter}=\\var{Num2*Num1}.\\]
\n
Use this link to find resources to help you revise how to solve linear equations
$\\var{Letter} =$
", "minValue": "{Num1*Num2}", "maxValue": "{Num1*Num2}", "correctAnswerFraction": false, "allowFractions": false, "mustBeReduced": false, "mustBeReducedPC": 0, "displayAnswer": "", "showFractionHint": true, "notationStyles": ["plain", "en", "si-en"], "correctAnswerStyle": "plain"}], "partsMode": "all", "maxMarks": 0, "objectives": [], "penalties": [], "objectiveVisibility": "always", "penaltyVisibility": "always", "contributors": [{"name": "Mash Sheffield", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4679/"}, {"name": "Andrew Neate", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/21832/"}], "resources": []}]}], "contributors": [{"name": "Mash Sheffield", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/4679/"}, {"name": "Andrew Neate", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/21832/"}]}