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Use defintions of the hyperbolic functions to integrate by considering exponentials.

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Use the algebraic definitions of the hyperbolic identities to evaluate the following integral.

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Don't forget to include '$+C$'!

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We will make use of the definition of $\\cosh(x)$, that is

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$$
\\cosh(ax) = \\frac{e^{ax} + e^{-ax}}{2}.
$$

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Therefore, we have

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$$
\\begin{aligned}
y &= \\int \\simplify{{A}e^({B}x) cosh({B}x)} \\, dx \\\\
&= \\int \\simplify{{A}e^({B}x)(e^({B}x) + e^(-{B}x))/2} \\, dx \\\\
&= \\simplify[all]{{A}/{2}} \\int \\simplify{e^({2B}x) + 1} \\, dx \\\\
&= \\simplify[all]{{A}/{4B}e^({2B}x) + {A}x/2} + C.
\\end{aligned}
$$

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$$y = \\int \\simplify{{A}e^({B}x) cosh({B}x)} \\, dx$$

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$y = $ [[0]]

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