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Please give your answers to 3 decimal places.
\nA student selects one card at random from a pack of 52 playing cards and then rolls a dice once.
\nLet event $A$ be that the card she picks is a $\\var{suit}$.
\nLet event $B$ be that the number she rolls is greater than $\\var{n}$.
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", "templateType": "anything"}}, "name": "Julie's copy of Select a card and roll a dice", "advice": "The outcome of selecting the card is independent of (not effected by) the outcome of rolling the dice.
\nIf two events, $A$ and $B$, are independent then $P(A\\cap B)=P(A)\\times P(B)$.
\nPart a)
\n\nLet $A$ represent the event that a $\\var{suit}$ is selected and let $B$ represent the event that a number greater than $\\var{n}$ is rolled.
\n$P(A)$ is $\\frac{13}{52}=\\frac{1}{4}$ and $P(B)$ is $\\frac{\\var{6-n}}{6}$.
\nTherefore the probability of drawing a $\\var{suit}$ and rolling a number greater than $\\var{n}$ is $ P(A) \\times P(B)=\\frac{1}{4} \\times \\frac{\\var{6-n}}{6}$.
\nPart b)
\n\nThe probability that neither of these events occur is the probability of not drawing a $\\var{suit}$ which is $P(A^c)=\\frac{3}{4}$ mulitiplied by the probability of not rolling a number greater than $\\var{n}$ which is $P(B^c)=\\frac{\\var{n}}{6}$ .
\nPart c)
\nThe probability that only one of these events occur is $P(A ^c\\cap B)+P(A \\cap B^c)=(\\frac{3}{4} \\times \\frac{\\var{6-n}}{6})+(\\frac{1}{4} \\times \\frac{\\var{n}}{6})$.
\nPart d)
\nThe probability that at least one of these two events will occur is $1- P$(neither of the events occur)$=1-(P(A^c)\\times P(B^c))= 1-(\\frac{3}{4}\\times \\frac{\\var{n}}{6})$
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