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The order of operation dictates that we deal with powers before multiplication/division and also deal with multiplication/division before addition/subtraction , that is 

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\var{d}+\\var{a}\\times\\var{b}^\\var{c}$$=$$\\var{d}+\\var{a}\\times\\var{b^c}$
$=$$\\var{d}+\\var{a*b^c}$
$=$$\\var{ans1}$
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$\\var{d}+\\var{a}\\times\\var{b}^\\var{c}=$ [[0]]

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Note: $\\var{h}(\\var{f}-\\var{g})$ means $\\var{h}\\times(\\var{f-g})$.

\n

\n

The order of operation dictates that we deal with brackets (grouping symbols) before multiplication, that is 

\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\var{h}(\\var{f}-\\var{g})$$=$$\\var{h}(\\var{f-g})$
$=$$\\var{ans2}$
\n

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$\\var{h}(\\var{f}-\\var{g})=$ [[0]]

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Note: A fraction $\\frac{a}{b}$ is the same as $(a)\\div (b)$, so we have to evaluate the numerator and denominator before doing the division. We can evaluate the numerator at the same time as we evaluate the denominator.

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\displaystyle{\\var{a}+\\frac{\\var{sub}^2-(\\var{base}-\\var{sub})^2}{-\\var{base}+2\\times\\var{sub}}}$$=$$\\displaystyle{\\var{a}+\\frac{\\var{sub}^2-(\\var{diff})^2}{-\\var{base}+2\\times\\var{sub}}}$(work on the innermost bracketed expression first)
$=$$\\displaystyle{\\var{a}+\\frac{\\var{subs}-\\var{diffs}}{-\\var{base}+2\\times\\var{sub}}}$(doing the powers on the numerator, and multiplication on the denominator)
$=$$\\displaystyle{\\var{a}+\\frac{\\var{num}}{-\\var{base}+\\var{tsub}}}$(doing multiplication on the denominator and addition on the numerator)
$=$$\\displaystyle{\\var{a}+\\frac{\\var{num}}{\\var{denom}}}$(continue working on the denominator)
$=$$\\displaystyle{\\var{a}+\\var{base}}$(do the division, or simplify the fraction)
$=$$\\var{ans3}$(finally do the last addition)
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$\\displaystyle{\\var{a}+\\frac{\\var{sub}^2-(\\var{base}-\\var{sub})^2}{-\\var{base}+2\\times\\var{sub}}} =$ [[0]]

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