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Sample Mean (1 dp)Sample Standard Deviation (3 sig figs)Median (exact value)Interquartile Range (exact value)
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Sample mean: The sample mean is $\\frac{\\var{sum(r0)}}{\\var{len(r0)}} = \\var{precround(mean(r0),1)}$ to 1 decimal place.

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Sample standard deviation: The sample standard deviation is $\\var{stdev(r0,true)}=\\var{siground(stdev(r0,true),3)}$ to 3 significant figures.

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If you order the data in increasing order you get the following table:

\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
$\\var{r1[0]}$$\\var{r1[1]}$$\\var{r1[2]}$$\\var{r1[3]}$$\\var{r1[4]}$$\\var{r1[5]}$$\\var{r1[6]}$$\\var{r1[7]}$
$\\var{r1[8]}$$\\var{r1[9]}$$\\var{r1[10]}$$\\var{r1[11]}$$\\var{r1[12]}$$\\var{r1[13]}$$\\var{r1[14]}$$\\var{r1[15]}$
$\\var{r1[16]}$$\\var{r1[17]}$$\\var{r1[18]}$$\\var{r1[19]}$$\\var{r1[20]}$$\\var{r1[21]}$$\\var{r1[22]}$$\\var{r1[23]}$
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Denote the ordered data by $x_j$, thus $x_{10}=\\var{r1[9]}$ for example.

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Median: The median lies between the 12th and 13th entries in the ordered table and is given by:

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\\[0.5\\times x_{12}+0.5\\times x_{13} = 0.5\\times\\var{r1[11]}+0.5\\times \\var{r1[12]}=\\var{median}\\]

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Interquartile range: As there is an even number of values, the Lower Quartile will lie between two values. Its position is calculated by finding

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\\[\\frac{n+1}{4}=\\frac{\\var{n+1}}{4}=6\\frac{1}{4}\\]

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Hence the Lower Quartile lies between the 6th and 7th entries in the ordered table.

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It is \\[0.75\\times x_6+0.25\\times x_7 = 0.75\\times\\var{r1[5]}+0.25\\times \\var{r1[6]}=\\var{lquartile}\\]

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Once again as there is an even number of values, the Upper Quartile will lie between two values and its position is calculated by finding

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\\[\\frac{3(n+1)}{4}=\\frac{\\var{3*(n+1)}}{4}=18\\frac{3}{4}\\]

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Hence the Upper Quartile lies between the 18th and 19th entries in the ordered table.

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We find it is \\[0.25\\times x_{18}+0.75\\times x_{19} = 0.25\\times\\var{r1[17]}+0.75\\times \\var{r1[18]}=\\var{uquartile}\\]

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The interquartile range is defined to be

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\\[ \\text{Upper Quartile} – \\text{Lower Quartile} \\]

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and so in this case we have:

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\\[ \\text{Interquartile range} = \\var{uquartile}-\\var{lquartile}=\\var{interq} \\]

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Sample of size $24$ is given in a table. Find sample mean, sample standard deviation, sample median and the interquartile range.

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The following data are the {whatever}, in {units}, of $\\var{n}$ {things} {description}

\n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n
$\\var{r0[0]}$$\\var{r0[1]}$$\\var{r0[2]}$$\\var{r0[3]}$$\\var{r0[4]}$$\\var{r0[5]}$$\\var{r0[6]}$$\\var{r0[7]}$
$\\var{r0[8]}$$\\var{r0[9]}$$\\var{r0[10]}$$\\var{r0[11]}$$\\var{r0[12]}$$\\var{r0[13]}$$\\var{r0[14]}$$\\var{r0[15]}$
$\\var{r0[16]}$$\\var{r0[17]}$$\\var{r0[18]}$$\\var{r0[19]}$$\\var{r0[20]}$$\\var{r0[21]}$$\\var{r0[22]}$$\\var{r0[23]}$
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