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Calculate the value of \\(x\\) that satisfies the following equation:

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\\(\\var{a}log(\\var{b}x+\\var{c})=\\var{d}\\)

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Input your answer correct to three decimal places.

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\\(x = \\) [[0]]

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Solve a logarithmic equation

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\\(\\var{a}log(\\var{b}x+\\var{c})=\\var{d}\\)

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Divide across by \\(\\var{a}\\)

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\\(log(\\var{b}x+\\var{c})=\\var{d}/\\var{a}=\\simplify{{d}/{a}}\\)

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\\(\\var{b}x+\\var{c}=10^{\\simplify{{d}/{a}}}\\)

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\\(\\var{b}x+\\var{c}=\\simplify{10^{{d}/{a}}}\\)

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\\(\\var{b}x=\\simplify{10^{{d}/{a}}}-\\var{c}\\)

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\\(\\var{b}x=\\simplify{10^{{d}/{a}}-{c}}\\)

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\\(x=\\simplify{(10^{{d}/{a}}-{c})/{b}}\\)

", "variablesTest": {"maxRuns": 100, "condition": ""}, "ungrouped_variables": ["a", "b", "c", "d"], "type": "question", "contributors": [{"name": "Nigel Atkins", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/275/"}]}]}], "contributors": [{"name": "Nigel Atkins", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/275/"}]}