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\$$x = \$$ [[0]]

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\$$\\var{k}=\\var{a}e^{\\var{m}x+{\\var{c}}}\$$

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\$$\\frac{\\var{k}}{\\var{a}}=e^{\\var{m}x+\\var{c}}\$$

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\$$ln\\left(\\frac{\\var{k}}{\\var{a}}\\right)=\\var{m}x+\\var{c}\$$

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\$$ln\\left(\\frac{\\var{k}}{\\var{a}}\\right)-\\var{c}=\\var{m}x\$$

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\$$\\frac{ln\\left(\\frac{\\var{k}}{\\var{a}}\\right)-\\var{c}}{\\var{m}}=x\$$

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Solve an exponential equation

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Given the equation \$$f(x)=\\var{a}e^{\\var{m}x+\\var{c}}\$$

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Determine the value for \$$x\$$ that satisfies the relation \$$f(x)=\\var{k}\$$

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