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Part 1:

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Add the ratio numbers and then divide the length by the summed total

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$\\frac{\\var{lent}}{\\var{summ}}$

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Then multiply each peice by the ratio length

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$\\var{numberone} \\times \\var{ratio}$

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$\\var{numbertwo} \\times \\var{ratio}$

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$\\var{numberthree} \\times \\var{ratio}$

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Part 2:

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Use the same method as in part 1

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$\\frac{\\var{total}}{(\\var{numberone1}+\\var{numbertwo1}+\\var{numberfour})}$

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$\\var{numberone} \\times \\var{k}$

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$\\var{numbertwo} \\times \\var{k}$

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$\\var{numberfour} \\times \\var{k}$

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Part 4:

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$(\\frac{\\var{money}}{(\\var{ratioab[0]} + \\var{ratioab[1]} + \\var{ratioc})}) \\times \\var{ratioab[0]} = \\var{ans31}$

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$(\\frac{\\var{money}}{(\\var{ratioab[0]} + \\var{ratioab[1]} + \\var{ratioc})}) \\times \\var{ratioab[1]} = \\var{ans32}$

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$(\\frac{\\var{money}}{(\\var{ratioab[0]} + \\var{ratioab[1]} + \\var{ratioc})})  \\times \\var{ratioc} = \\var{ans33}$

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Ratio Questions

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rebel

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rebelmaths

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Verdeel het stuk $\\var{material}$ in $\\var{numberone}$ + $\\var{numbertwo}$ +$\\var{numberthree}$ stukken. Welke lengte bekom je dan?

Het eerste stuk zou $\\var{numberone}$ keer die lengte moeten zijn.   Het tweede stuk zou $\\var{numbertwo}$ keer die lengte moeten zijn. Het derde stuk zou $\\var{numberthree}$ keer die lengte moeten zijn.

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Controleer of de som van deze stukken terug $\\var{lent}$ is.

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Een stuk $\\var{material}$ van $\\var{lent}$ cm lang wordt verdeeld in drie stukken met een verhouding van $\\var{numberone}$ tot $\\var{numbertwo}$ tot $\\var{numberthree}$. Bepaal de lengte van deze stukken. 

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[[0]]cm

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[[1]]cm

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[[2]]cm

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Vul de delen in.

", "type": "question", "contributors": [{"name": "Johan Maertens", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1301/"}]}]}], "contributors": [{"name": "Johan Maertens", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1301/"}]}