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This question assesses

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The question also helps to show students how using experimental probability and theoretical probability results in different expected values of an outcome.

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{pname} rolls an unbiased six-sided die $\\var{no_rolls}$ times.

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a)

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Firstly, we must calculate the theoretical probability of rolling either a $\\var{num1}$ or a $\\var{num2}$.

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Both $\\var{num1}$ and $\\var{num2}$ only appear once on an unbiased six-sided die, so there are only $2$ possible outcomes where we roll either a $\\var{num1}$ or a $\\var{num2}$.

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There are $6$ possible outcomes when we roll an unbiased six-sided die.

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Therefore, the theoretical probability of rolling either a $\\var{num1}$ or a $\\var{num2}$ is

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\\[\\displaystyle\\frac{2}{6} = \\displaystyle\\frac{1}{3}.\\]

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Then the expected number of times that {pname} rolls either a $\\var{num1}$ or a $\\var{num2}$ is

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\\[\\var{no_rolls} \\times \\displaystyle\\frac{1}{3} = \\var{{no_rolls}/3}.\\]

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b)

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We are told that in {pronouns['their']} experiment, {pname} obtained either a $\\var{num1}$ or a $\\var{num2}$ on $\\var{Obtained}$ occasions. 

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Recall the formula for the relative frequency of an outcome.

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\\[ \\text{Relative Frequency} = \\displaystyle\\frac{\\text{Frequency of an outcome}}{\\text{Number of trials}}.\\]

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The Number of trials in the experiment is $\\var{no_rolls}$ and the frequency of the desired outcome is $\\var{Obtained}$.

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So the relative frequency of rolling either a $\\var{num1}$ or a $\\var{num2}$ is $\\displaystyle\\frac{\\var{Obtained}}{\\var{no_rolls}}$.

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c)

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The same die is now thrown $\\var{more_rolls}$ times.

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We know from b) that the relative frequency of rolling either a $\\var{num1}$ or a $\\var{num2}$ with this die was $\\displaystyle\\simplify{{Obtained}/{no_rolls}}$.

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Therefore using the experimental data, the number of times we would expect {pname} to roll either a $\\var{num1}$ or a $\\var{num2}$ in $\\var{more_rolls}$ throws of the die is

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\\[\\var{more_rolls} \\times \\displaystyle\\simplify{{Obtained}/{no_rolls}} = \\var{{more_rolls}*{Obtained}/{no_rolls}}.\\]

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On the other hand, we know from a) that the theoretical probability of rolling either a $\\var{num1}$ or a $\\var{num2}$ with this die is $\\displaystyle\\frac{1}{3}$.

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Using the theoretical probability, the number of times we would expect {pname} to roll either a $\\var{num1}$ or a $\\var{num2}$ in $\\var{more_rolls}$ throws of the die is 

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\\[\\var{more_rolls} \\times \\displaystyle\\frac{1}{3} = \\var{{more_rolls}/3}.\\]

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Second number.

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Number of times the event is obtained in the experiment.

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Number of rolls of the die.

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multiplier for the value of Obtained variable

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First number.

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Number of extra rolls of the die

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Based on the theoretical probability of rolling a $\\var{num1}$ or a $\\var{num2}$, how many times would you expect {pronouns['them']} to roll either one of these numbers?

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After performing the experiment, {pname} reports that {pronouns['they']} rolled either a $\\var{num1}$ or a $\\var{num2}$ on $\\var{Obtained}$ occasions.

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Calculate the relative frequency of rolling either a $\\var{num1}$ or a $\\var{num2}$.

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Enter your answer as a fraction.

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$\\text{Relative Frequency} =$ [[0]]

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If {pname} rolled the same die $\\var{more_rolls}$ more times, how many times could {pronouns['they']} expect to roll either a $\\var{num1}$ or a $\\var{num2}$?

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Based on the experimental data: [[0]]

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Based on the theoretical probability: [[1]]

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