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$\\displaystyle\\frac{\\var{a}}{\\var{b}}+\\frac{\\var{c}}{\\var{b}}=$[[0]]

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$\\displaystyle\\frac{\\var{d}}{\\var{c}}-\\frac{\\var{a}}{\\var{c}}=$[[1]]

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Legg sammen tellerne, behold nevner.

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Disse brøkene har felles nevner, og kan enkelt legges sammen. La oss illustrere det med eksempler (som ikke er like oppgaven): 

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\\[\\frac{2}{3}+\\frac{5}{3}=\\frac{2+5}{3}=\\frac{7}{3}\\]

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Den samme fremgangsmåten kan brukes for subtraksjon: 

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\\[\\frac{7}{4}-\\frac{3}{4}=\\frac{7-3}{4}=\\frac{4}{4}=1\\]

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Regn ut

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$\\displaystyle\\simplify{{h}/{f}-{j}/{g}}=$  [[0]]

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$\\displaystyle \\frac{\\var{a}}{\\var{d}}+\\var{f}=$ [[1]]

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Utvid brøkene slik at de får en felles nevner. Deretter kan du addere eller subtrahere slik som i forrige oppgave. 

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Hvis oppgaven var $\\frac{5}{4}+\\frac{3}{8}$ kunne vi utvidet den første brøken til $\\frac{10}{8}$ (ved å multiplisere med 2 i teller og nevner), slik at begge brøkene fikk nevner lik 8. Deretter kunne vi addert brøkene: 

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\\[\\frac{5}{4}+\\frac{3}{8}=\\frac{5\\cdot 2}{4\\cdot 2}+\\frac{3}{8}=\\frac{10}{8}+\\frac{3}{8}=\\frac{13}{8}\\]

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Som regel må vi utvide begge brøkene for å få en felles nevner, for eksempel når vi skal regne ut  $\\frac{5}{4}-\\frac{2}{3}$. Her kan 12 være en felles nevner, og utregningen kan se slik ut: 

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\\[\\frac{5}{4}-\\frac{2}{3}=\\frac{5\\cdot 3}{4\\cdot 3}-\\frac{2\\cdot 4}{3\\cdot 4}=\\frac{15}{12}-\\frac{8}{12}=\\frac{7}{12}\\]

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Et godt valg for fellesnevneren er minste felles multiplum til de to nevnerne.

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NB! Husk at hele tall kan skrives som en brøk med nevner lik 1, for eksempel $3=\\frac{3}{1}$.

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Add, subtract, multiply and divide numerical fractions.

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Regn ut og oppgi svaret ditt som en brøk eller et helt tall (ikke desimaltall). Bruk  /  som brøkstrek, for eksempel skal $\\frac{2}{3}$ skrives som 2/3.

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Learn from your mistakes and have another attempt by clicking on 'Try another question like this one' until you get full marks.

", "contributors": [{"name": "Daniel Meselu", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1671/"}]}]}], "contributors": [{"name": "Daniel Meselu", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1671/"}]}