// Numbas version: exam_results_page_options
{"name": "Lovkush's copy of Randomly give two of hypotenuse, opposite, and adjacent side of a triangle", "extensions": [], "custom_part_types": [], "resources": [], "navigation": {"allowregen": true, "showfrontpage": false, "preventleave": false, "typeendtoleave": false}, "question_groups": [{"pickingStrategy": "all-ordered", "questions": [{"functions": {}, "parts": [{"marks": 0, "type": "gapfill", "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "showCorrectAnswer": true, "prompt": "<p>What is the length of the {missing}?</p>\n<p>[[0]]m</p>", "scripts": {}, "gaps": [{"type": "numberentry", "correctAnswerFraction": false, "maxValue": "sides[missing]", "showCorrectAnswer": true, "mustBeReducedPC": 0, "minValue": "sides[missing]", "allowFractions": false, "marks": 1, "notationStyles": ["plain", "en", "si-en"], "showFeedbackIcon": true, "variableReplacements": [], "variableReplacementStrategy": "originalfirst", "correctAnswerStyle": "plain", "scripts": {}, "mustBeReduced": false}]}], "variable_groups": [], "variables": {"missing": {"group": "Ungrouped variables", "definition": "random(keys(sides))", "templateType": "anything", "name": "missing", "description": "<p>The name of the side which the student has to work out.</p>"}, "first_given": {"group": "Ungrouped variables", "definition": "if(missing=\"opposite side\",\"adjacent side\",\"opposite side\")", "templateType": "anything", "name": "first_given", "description": "<p>The name of the first side given&nbsp;to the student.</p>"}, "hypotenuse": {"group": "Ungrouped variables", "definition": "adjacent+1", "templateType": "anything", "name": "hypotenuse", "description": "<p>The length of the hypotenuse.</p>"}, "adjacent": {"group": "Ungrouped variables", "definition": "(opposite^2-1)/2", "templateType": "anything", "name": "adjacent", "description": "<p>The length of the adjacent side. The sides will always form a Pythagorean triple.</p>"}, "opposite": {"group": "Ungrouped variables", "definition": "random(3..13#2)", "templateType": "anything", "name": "opposite", "description": "<p>The length of the opposite side.</p>"}, "sides": {"group": "Ungrouped variables", "definition": "[\"opposite side\":opposite,\"adjacent side\":adjacent,\"hypotenuse\":hypotenuse]", "templateType": "anything", "name": "sides", "description": "<p>A dictionary giving the lengths of the sides. Used in the statement and to set the correct answer.</p>"}, "second_given": {"group": "Ungrouped variables", "definition": "if(missing=\"hypotenuse\",\"adjacent side\",\"hypotenuse\")", "templateType": "anything", "name": "second_given", "description": "<p>The name of the second side given to the student.</p>"}, "signs": {"group": "Ungrouped variables", "definition": "[\"opposite side\": 1, \"adjacent side\": 1, \"hypotenuse\": -1]", "templateType": "anything", "name": "signs", "description": "<p>Signs of each of the components in the equation $a^2 + b^2 - c^2 = 0$. Used in the working-out in the advice.</p>\n<p>In the equation $\\text{missing} = \\sqrt{ \\pm \\text{first}^2 \\pm \\text{second}^2}$, note that:</p>\n<ul>\n<li>when the hypotenuse is missing, both sides in the square root are positive: $\\sqrt{ \\text{first}^2 + \\text{second}^2} = \\sqrt{a^2+b^2}$</li>\n<li>when either of the other sides is missing, it's $\\sqrt{- \\text{first}^2 + \\text{second}^2} = \\sqrt{-(a \\text{ or } b)^2 + c^2}$.</li>\n</ul>\n<p>So, only the first side in the square root changes sign depending on the missing side.</p>"}}, "metadata": {"licence": "Creative Commons Attribution 4.0 International", "description": "<p>Some clever variable-substitution trickery to randomly pick two sides of a right-angled triangle to give to a student, and ask for the other.</p>\n<p>The sides are set up so they're always Pythagorean triples, and the opposite side is always odd.</p>\n<p>As ever, most of the tricky stuff is in the advice.&nbsp;</p>\n<p>Because this was created quickly to show how to&nbsp;set up the randomisation, there's no diagram. It would benefit greatly from a diagram.</p>"}, "statement": "<p>You are told that a triangle has {first_given} side {sides[first_given]}m, and {second_given} side {sides[second_given]}m.</p>", "name": "Lovkush's copy of Randomly give two of hypotenuse, opposite, and adjacent side of a triangle", "ungrouped_variables": ["opposite", "adjacent", "hypotenuse", "sides", "missing", "first_given", "second_given", "signs"], "tags": [], "advice": "<p>We are given the {first_given} and the {second_given}.</p>\n<p>We can use Pythagoras' theorem to work out the {missing}.</p>\n<p>Pythagoras' theorem states that</p>\n<p>\\[ a^2 + b^2 = c^2 \\text{,} \\]</p>\n<p>where $a$ is the opposite&nbsp;side, $b$ is the adjacent side, and $c$ is the hypotenuse.</p>\n<p>Substituting the values into&nbsp;this equation, we have</p>\n<p><span data-jme-visible=\"missing=&quot;hypotenuse&quot;\">\\[ \\var{opposite}^2 + \\var{adjacent}^2 = c^2 \\]</span><span data-jme-visible=\"missing=&quot;adjacent side&quot;\">\\[ \\var{opposite}^2 + b^2 = \\var{hypotenuse}^2 \\]</span><span data-jme-visible=\"missing=&quot;opposite side&quot;\">\\[ a^2&nbsp;+ \\var{adjacent}^2 = \\var{hypotenuse}^2 \\]</span></p>\n<p>So the {missing} is</p>\n<p>\\[ \\simplify[noleadingminus,unitfactor]{ sqrt({signs[second_given]}*{sides[first_given]}^2 + {sides[second_given]}^2)} = \\sqrt{\\var{sides[missing]^2}} = \\var{sides[missing]}\\text{m} \\]</p>", "variablesTest": {"maxRuns": 100, "condition": ""}, "rulesets": {}, "extensions": [], "preamble": {"css": "", "js": ""}, "type": "question", "contributors": [{"name": "Lovkush Agarwal", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1358/"}]}]}], "contributors": [{"name": "Lovkush Agarwal", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/1358/"}]}