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Solve for x in each of the following:

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Enter answer as whole number or fraction

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Indices

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rebelmaths

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$2^{\\var{num11}x-\\var{num12}} = \\var{nn1}^{x+\\var{num13}}$

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x = [[0]]

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$\\var{nn21}^{x-\\var{num21}} = \\var{nn22}^{\\var{num22} - x}$

\n

x= [[0]]

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$\\var{nn31}^{\\var{num31}x+\\var{num32}} = \\frac{1}{\\var{nn32}}$

\n

x = [[0]]

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$\\var{nn41}^{\\var{num41}x-\\var{num42}} = \\var{nn42}^{\\var{num43} - x}$

\n

x = [[0]]

", "scripts": {}, "marks": 0, "variableReplacementStrategy": "originalfirst", "variableReplacements": []}], "functions": {}, "advice": "

i) $2^{4x-3} = 4^{x+1}$

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$2^{4x-3} = 2^{2x+2}$

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$4x-3 = 2x+2$

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$4x-2x = 3+2$

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$x = \\frac{5}{2}$

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ii) $9^{x-4} = 27^{2-x}$

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$3^{2x-8} = 3^{6-3x}$

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$2x-8 = 6-3x$

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$2x+3x = 6+8$

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$x = \\frac{14}{5}$

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iii) $2^{2x+3} = \\frac{1}{4}$

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$2^{2x+3} = 2^{-2}$

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$2x+3 = -2$

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$2x = -2-3$

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$x = \\frac{-5}{2}$

\n

\n

iv) $25^{2x-3} = 5^{4-x}$

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$5^{4x-6} = 5^{4-x}$

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$4x-6 = 4-x$

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$4x+x = 4+6$

\n

$x = 2$

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