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The function $g(x)$ is continuous and differentiable at all points in $\\mathbb{R}$.
\nUsing the quotient rule for differentiation we see that
\\[\\begin{eqnarray*}g'(x)&=&\\simplify{({a}*(x^2+{b^2})-{2*a}*x^2)/(x^2+{b^2})^2}\\\\ &=&\\simplify{({-a}*(x-{b})(x+{b}))/(x^2+{b^2})^2} \\end{eqnarray*} \\]
The stationary points are given by solving $g'(x)=0$.
\n$g'(x)=0 \\Rightarrow \\simplify{{-a}*(x-{b})(x+{b})=0} \\Rightarrow x=\\var{b} \\mbox{ or } x=\\var{-b}$
\nWe see that both stationary points are in the inerval $I$.
\nThe second derivative can be found by applying the quotient rule to the derivative of $g(x)$ and we obtain:
\nUsing the quotient rule for differentiation we see that
\\[\\begin{eqnarray*}g''(x)&=&\\simplify[std]{({-2*a}*x*(x^2+{b^2})^2+{4*a}*x*(x^2-{b^2})(x^2+{b^2}))/(x^2+{b^2})^4}\\\\ &=&\\simplify[std]{({2*a}*x*(x^2-{3*b^2}))/(x^2+{b^2})^3} \\end{eqnarray*} \\]
The nature of the stationary points are determined by evaluating $g''(x)$ at the stationary points.
\nFor $x= \\var{lma}$ we have: \\[g''(\\var{lma})= \\simplify[std]{-{abs(a)}/{2*b^3}} \\lt 0\\]
\nHence is a local maximum.
\nEvaluating the function at $x=\\var{lma}$ gives $g(\\var{lma})=\\var{valmax}$ to 3 decimal places.
\nFor $x= \\var{lmi}$ we have: \\[g''(\\var{lmi})= \\simplify[std]{{abs(a)}/{2*b^3}} \\gt 0\\]
\nHence is a local minimum.
\nEvaluating the function at $x=\\var{lmi}$ gives $g(\\var{lmi})=\\var{valmin}$ to 3 decimal places.
\nThe values of $g$ at the endpoints are:
\n$g(\\var{c})=\\var{valbegin}$ and $g(\\var{d})=\\var{valend}$ to 3 decimal places.
\nSince $g$ has a finite limit of $0$ as $x \\rightarrow \\pm\\infty$ and we have that $0$ lies between the local minimum value $\\var{valmin}$ and the local maximum value $\\var{valmax}$ (and these occur at values in $I$).
\nthen:
\nGlobal Maximum: The local maximum of $g$ we have found at $x=\\var{lma} \\in I$ must be a global maximum and similarly,
\nGlobal Minimum: The local minimum of $g$ we have found at $x=\\var{lmi} \\in I$ must be a global minimum.
\nSo we have shown \\[\\forall x \\in \\mathbb{R},\\;\\;\\var{valmin} \\le g(x) \\le \\var{valmax}\\]
\n(all to 3 decimal places).
", "rulesets": {"std": ["all", "!collectNumbers", "fractionNumbers", "!noLeadingMinus"]}, "parts": [{"displayColumns": 0, "prompt": "\nIs $g(x)$ continuous at all points of $I$?
\n \nChoose Yes or No.
\n \n ", "matrix": [1, 0], "shuffleChoices": false, "maxMarks": 0, "distractors": ["", ""], "choices": ["Yes
", "No
"], "displayType": "radiogroup", "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "1_n_2", "minMarks": 0}, {"prompt": "\nThe first derivative of $g$ can be written in the form $\\displaystyle \\frac{p(x)}{q(x)}$ where $p(x)$ and $q(x)=(x^2+\\var{b^2})^2$ are polynomials.
\nInput the numerator $p(x)$ of the first derivative of $g$ here, factorised into a product of two linear factors in the form
\\[p(x)=c(x-a)(x-b)\\]for suitable integers $a$, $b$ and $c$:
$p(x)=\\;\\;$[[0]]
\n ", "marks": 0, "gaps": [{"notallowed": {"message": "Factorise the expression
", "showStrings": false, "strings": ["^", "x*x", "xx", "x x"], "partialCredit": 0}, "expectedvariablenames": [], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "vsetrangepoints": 5, "showCorrectAnswer": true, "answersimplification": "std", "scripts": {}, "answer": "({( - a)} * (x + ( - {b})) * (x + {b}))", "marks": 1, "checkvariablenames": false, "checkingtype": "absdiff", "type": "jme", "musthave": {"message": "Factorise the expression
", "showStrings": false, "strings": ["(", ")"], "partialCredit": 0}}], "showCorrectAnswer": true, "scripts": {}, "type": "gapfill"}, {"displayColumns": 0, "prompt": "\nIs $g(x)$ differentiable at all points of $I$?
\n \nChoose Yes or No.
\n \n ", "matrix": [1, 0], "shuffleChoices": true, "maxMarks": 0, "distractors": ["", ""], "choices": ["Yes
", "No
"], "displayType": "radiogroup", "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "1_n_2", "minMarks": 0}, {"prompt": "\nAssume now that $g$ is a function $g:\\mathbb{R} \\rightarrow \\mathbb{R}$.
\n \nLeast stationary point: [[0]]
\n \nGreatest stationary point: [[1]]
\n \nAre both stationary points in the interval $I$? Choose Yes or No.
[[2]]
Yes
", "No
"], "displayType": "radiogroup", "showCorrectAnswer": true, "scripts": {}, "marks": 0, "type": "1_n_2", "minMarks": 0}], "showCorrectAnswer": true, "scripts": {}, "type": "gapfill"}, {"prompt": "\nThe second derivative of $g$ can be written in the form $\\displaystyle \\frac{r(x)}{s(x)}$ where $r(x)$ and $s(x)=(x^2+\\var{b^2})^3$ are polynomials.
\nInput the numerator $r(x)$ of the second derivative of $g$ here, factorised into a product of a linear factor and a quadratic factor in the form
\\[r(x)=a_1x(x^2-a_2)\\] for suitable integers $a_1$, $a_2$
$r(x)=\\;\\;$ [[0]]
\nHence find all local maxima and minima given by the stationary points
\nLocal maximum is at $x=\\;\\;$ [[1]] and the value of the function at the local maximum (to 3 decimal places)= [[2]]
\nLocal minimum is at $x=\\;\\;$ [[3]] and the value of the function at the local minimum (to 3 decimal places) = [[4]]
\n ", "marks": 0, "gaps": [{"notallowed": {"message": "Factorise the expression
", "showStrings": false, "strings": ["x^2", "x x", "xx"], "partialCredit": 0}, "expectedvariablenames": [], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "vsetrangepoints": 5, "showCorrectAnswer": true, "answersimplification": "std", "scripts": {}, "answer": "{2*a}*x*(x^2-{3*b^2})", "marks": 1, "checkvariablenames": false, "checkingtype": "absdiff", "type": "jme", "musthave": {"message": "Factorise the expression
", "showStrings": false, "strings": ["(", ")"], "partialCredit": 0}}, {"expectedvariablenames": [], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "vsetrangepoints": 5, "showCorrectAnswer": true, "answersimplification": "std", "scripts": {}, "answer": "{lma}", "marks": 1, "checkvariablenames": false, "checkingtype": "absdiff", "type": "jme"}, {"allowFractions": false, "marks": 1, "maxValue": "{valmax+tol}", "minValue": "{valmax-tol}", "correctAnswerFraction": false, "showCorrectAnswer": true, "scripts": {}, "type": "numberentry", "showPrecisionHint": false}, {"expectedvariablenames": [], "checkingaccuracy": 0.001, "vsetrange": [0, 1], "showpreview": true, "vsetrangepoints": 5, "showCorrectAnswer": true, "answersimplification": "std", "scripts": {}, "answer": "{lmi}", "marks": 1, "checkvariablenames": false, "checkingtype": "absdiff", "type": "jme"}, {"allowFractions": false, "marks": 1, "maxValue": "{valmin+tol}", "minValue": "{valmin-tol}", "correctAnswerFraction": false, "showCorrectAnswer": true, "scripts": {}, "type": "numberentry", "showPrecisionHint": false}], "showCorrectAnswer": true, "scripts": {}, "type": "gapfill"}, {"prompt": "\nWhat are the following values at the end points of the interval $I$ ?
\n \n$g(\\var{c})=\\;\\;$ [[0]]
\n \n$g(\\var{d})=\\;\\;$ [[1]]
\n \nInput both to 3 decimal places.
\n \n ", "marks": 0, "gaps": [{"allowFractions": false, "marks": 1, "maxValue": "precround(valbegin+0.001,3)", "minValue": "precround(valbegin-0.001,3)", "correctAnswerFraction": false, "showCorrectAnswer": true, "scripts": {}, "type": "numberentry", "showPrecisionHint": false}, {"allowFractions": false, "marks": 1, "maxValue": "precround(valend+0.001,3)", "minValue": "precround(valend-0.001,3)", "correctAnswerFraction": false, "showCorrectAnswer": true, "scripts": {}, "type": "numberentry", "showPrecisionHint": false}], "showCorrectAnswer": true, "scripts": {}, "type": "gapfill"}, {"prompt": "\nAssume now that $g: \\mathbb{R} \\rightarrow \\mathbb{R}$ and you are given that:
\n \n$\\lim_{x \\to \\infty}g(x)=0$ and $\\lim_{x \\to -\\infty}g(x)=0$
\n \nAt what value of $x \\in I$ does $g$ have a global maximum ?
\n \n$x=\\;\\;$ [[0]]
\n \nAt what value of $x \\in I$ does $g$ have a global minimum ?
\n \n$x=\\;\\;$ [[1]]
\n \n ", "marks": 0, "gaps": [{"allowFractions": false, "marks": 1, "maxValue": "{lma}", "minValue": "{lma}", "correctAnswerFraction": false, "showCorrectAnswer": true, "scripts": {}, "type": "numberentry", "showPrecisionHint": false}, {"allowFractions": false, "marks": 1, "maxValue": "{lmi}", "minValue": "{lmi}", "correctAnswerFraction": false, "showCorrectAnswer": true, "scripts": {}, "type": "numberentry", "showPrecisionHint": false}], "showCorrectAnswer": true, "scripts": {}, "type": "gapfill"}], "statement": "\nLet $I=[\\var{c},\\var{d}]$ be an interval and let $g: I \\rightarrow I$ be the function given by:
\\[g(x)=\\simplify{{a}*x/(x^2+{b}^2)}\\]
Answer the following questions. There are seven parts and you may need to scroll down to complete all parts.
\n \n ", "type": "question", "variable_groups": [], "variablesTest": {"maxRuns": 100, "condition": ""}, "variables": {"a": {"definition": "s*random(1..9)", "templateType": "anything", "group": "Ungrouped variables", "name": "a", "description": ""}, "c": {"definition": "-b-random(1..3)", "templateType": "anything", "group": "Ungrouped variables", "name": "c", "description": ""}, "b": {"definition": "random(1..9)", "templateType": "anything", "group": "Ungrouped variables", "name": "b", "description": ""}, "d": {"definition": "b+random(1..3)", "templateType": "anything", "group": "Ungrouped variables", "name": "d", "description": ""}, "valmax": {"definition": "-valmin", "templateType": "anything", "group": "Ungrouped variables", "name": "valmax", "description": ""}, "valend": {"definition": "precround(a*d/(d^2+b^2),3)", "templateType": "anything", "group": "Ungrouped variables", "name": "valend", "description": ""}, "lmi": {"definition": "if(a<0,b,-b)", "templateType": "anything", "group": "Ungrouped variables", "name": "lmi", "description": ""}, "s": {"definition": "random(1,-1)", "templateType": "anything", "group": "Ungrouped variables", "name": "s", "description": ""}, "tol": {"definition": "0.001", "templateType": "anything", "group": "Ungrouped variables", "name": "tol", "description": ""}, "valbegin": {"definition": "precround(a*c/(c^2+b^2),3)", "templateType": "anything", "group": "Ungrouped variables", "name": "valbegin", "description": ""}, "lma": {"definition": "if(a>0,b,-b)", "templateType": "anything", "group": "Ungrouped variables", "name": "lma", "description": ""}, "valmin": {"definition": "precround(-abs(a)*b/(2*b^2),3)", "templateType": "anything", "group": "Ungrouped variables", "name": "valmin", "description": ""}}, "metadata": {"notes": "\n \t\t9/07/2012:
\n \t\tAdded tags.
\n \t\tCorrected mistake in Advice ($x$ instead of $x^2$).
\n \t\tTolerance variable set to tol=0.001 for a numeric entry.
\n \t\t\n \t\t
10/07/2012:
Added tags.
\n \t\tEdited grammar in the Advice section.
Question appears to be working correctly.
\n \t\t", "description": "$I$ compact interval. $\\displaystyle g: I \\rightarrow I, g(x)=\\frac{ax}{x^2+b^2}$. Find stationary points and local maxima, minima. Using limits, has $g$ a global max, min?
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