Answer the following:
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"}, "advice": "When $n$ is positive, we multiply $10$ by itself $n$ times,
\n\\[\\text{e.g. } 10^3 = 10 \\times 10 \\times 10 = 1000 \\text{ .}\\]
\nWhen $n$ is negative, we can think of $10^{-n}$ as $\\frac{1}{10^{n}}$,
\n\\[\\text{e.g. } 10^{-3} = \\frac{1}{10^3} = \\frac{1}{1000} = 0.001\\text{ .}\\]
\nWhen $n = 0$:
\n\\[10^{0} = 1 \\text{ .}\\]
\nGenerally, we can think of $10^n$ as a number in standard form $1 \\times 10^n$. Then $n$ always tells us the number of decimal places to move the decimal point in $1.0$, for example
\n\\[10^{-3} = 1.0 \\times 10^{-3} \\text{ and since } n = - 3 \\text{, we go } 3 \\text{ places back as follows: } 1.0 ⇒ 0.1 ⇒ 0.01 ⇒ 0.001 \\text{ .}\\]
\nA complete table of powers of ten for $n$ from $-6$ to $6$ is:
\n| $n$ | \n$10^n$ | \n
|---|---|
| $-6$ | \n$0.000001$ | \n
| $-5$ | \n$0.00001$ | \n
| $-4$ | \n$0.0001$ | \n
| $-3$ | \n$0.001$ | \n
| $-2$ | \n$0.01$ | \n
| $-1$ | \n$0.1$ | \n
| $0$ | \n$1$ | \n
| $1$ | \n$10$ | \n
| $2$ | \n$100$ | \n
| $3$ | \n$1000$ | \n
| $4$ | \n$10000$ | \n
| $5$ | \n$100000$ | \n
| $6$ | \n$1000000$ | \n
Use the table below to find $w'(\\var{b})$ if $w(x)=h(g(x))$.
\n\n| $x$ | \n$g(x)$ | \n$g'(x)$ | \n$h(x)$ | \n$h'(x)$ | \n
|---|---|---|---|---|
| 1 | \n3 | \n$\\var{gp[0]}$ | \n3 | \n$\\var{hp[0]}$ | \n
| 2 | \n1 | \n$\\var{gp[1]}$ | \n2 | \n$\\var{hp[1]}$ | \n
| 3 | \n2 | \n$\\var{gp[2]}$ | \n1 | \n$\\var{hp[2]}$ | \n
$w'(\\var{b})=$[[0]]
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