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The divergence test says that if the sequence of $t_k$ diverges or converges to a non-zero number then the series $\\sum_{k=a}^\\infty t_k$ diverges. Notice it does not tell us anything about the series if the sequence of $t_k$ converges to $0$. Another way to think about this is, for a series to have any
a)
\nSince each term in the series is getting {text} in absolute value the sequence can never 'settle down' or 'approach' a finite number. In other words, the sequence diverges (does not converge) and so the divergence test implies that the series diverges.
\nSince each term in the series is getting {text} in absolute value the sequence 'settles down' and 'approaches' zero. In other words, the sequence converges to zero and so the divergence test doesn't actually tell us anything about the series (it may or may not converge).
\n\nb)
\nSince the limit of the sequence does not exist, the sequence diverges (diverges just means does not converge) and so the divergence test tells us that the series diverges.
\nSince the limit of the sequence is a non-zero number ($\\var[fractionNumbers]{limit}$) the divergence test tells us that the series diverges.
\nSince the limit of the sequence is zero, the divergence test doesn't actually tell us anything about whether the series converges or diverges.
\n\nc)
\nTo use the divergence test we need to determine whether the sequence of terms approach zero or not. Consider
\n{cexpression} as $k\\rightarrow \\infty$.
\n\n\nAs $k$ gets larger and larger our terms get larger and larger. This means that the limit does not exist (or sometimes people prefer to say the limit equals infinity) and so the divergence test tells us that the series diverges.
\n\nAs $k$ gets larger and larger our terms get larger and larger in absolute value but alternate in sign. This means that the limit does not exist and so the divergence test tells us that the series diverges.
\n\nAs $k$ gets larger and larger our terms jump around, they get positive, negative, smaller, larger... The terms do not approach a constant. This means that the limit does not exist and so the divergence test tells us that the series diverges.
\n\nAs $k$ gets larger and larger our terms approach zero. The larger $k$ gets, the closer to zero the terms become. This means that the sequence converges to $0$ and so the divergence test does not tell us anything about whether the series converges or diverges.
\n\nAs $k$ gets larger and larger our terms approach a non-zero constant. The larger $k$ gets, the closer to this non-zero constant the terms become. This means that the sequence converges to this non-zero constant and so the divergence test tells us that the series diverges.
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\n$\\displaystyle\\sum_{k=\\var{start}}^\\infty$ {cexpression}
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\nThis is really 'diverge but stay bounded'.
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This question is about the divergence test for series.
", "type": "question", "contributors": [{"name": "Ben Brawn", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/605/"}]}]}], "contributors": [{"name": "Ben Brawn", "profile_url": "https://numbas.mathcentre.ac.uk/accounts/profile/605/"}]}